Problem How to exclude some of the words before storing in array

kishore2k9

hi please slove my problem in php,

user input from form textarea is -->ex:text1=

2.php file

from the above code i have to get only the words which are not in th excluded list..but from the above code i'm getting some of the excluded words also pls slove this..i.e its not excluding some of the words

pls give the solution

bretticus

At first glance, I cannot pretend to understand what the @ (at sign) business is all about. However, why not just build regular expression patterns for your words to exclude? You certainly can specify word boundaries (I believe the beginning and end of a string qualify as word boundaries) to exclude whole words only without ever having to split your original string. Here's an example.

$words_to_exclude=array();
$result = mysql_query("select words from words_eliminate");

while($row = mysql_fetch_array($result))
{
	$words_to_exclude[]="/\b".preg_quote($row['words'],"/")."\b/gi" ;
}
$old_string = trim($_POST['text1']);
$new_string = preg_replace($words_to_exclude, "", $old_string);

devphp12

try this one if helpful

<?php
$text="Admanya, India's first consumer education cum advocacy website listens to the consumers and not just hear them. Admanya is the best platform for consumers to voice their opinions, compare the product features and service quality, read user reviews, build relationships through interactive exchanges, and get detailed product information about different brands. You can also create your own space through profile, blogs, discussion and comments";

echo $text." ";
$newarray1=array();
$exclude_words1 =array();

$newarray1[]="@ to @" ;
$newarray1[]="@ about @" ;
$newarray1[]="@ and @" ;
$newarray1[]="@ amp @" ;
$newarray1[]="@ at @" ;
$newarray1[]="@ admanya @" ;
$newarray1[]="@ first @";

//triming the user given value first
$s=strtolower(trim($text));
//i have to exclude the following words in the user given string for that i'm using below variable and storing in array those

$exclude_words1 =$newarray1;

$s3 = preg_replace($exclude_words1, ' ', $s);
$exclude_symbs = array('@[0-9]@','@.@','@\,@','@:@','@"@','@\?@','@(@','@)@','@!@','@\/@','@\&@','@\ @');
$exclude_words1 = array('to','admanya','amp','about','and','first','at');

$s1 = preg_replace($exclude_symbs, " ", strtolower(trim($s3))); // Strip excluded symbols
/
echo strtolower($s1)."------ ";;
echo " ";/

$words = explode(' ',strtolower($s1));

//print_r($words);

$word_final=array();
//print_r($exclude_words1);
for($i=0;$i<count($words);$i++)
{

if(!(in_array($words[$i],$exclude_words1)))
{	//echo $words[$i]."--$i<br>";
	$word_final[]=$words[$i];
}

}

print_r($word_final);
echo " ";

kishore2k9

if any value in array is empty i.e []
ex:Array ( [product] => 2 [consumers] => 2 [] => 2 [service] => 2 [through] => 2)
then i have to delete that data in array and store the data in another array only which has values without null or empty can help on this.. how to elimate if data is like this [] in array.
and i have to get the result only the data while is not[] null like that in array and store the data in array only the data without null and []

the result of my ouput should be store in array like:
present output:
Array ( [product] => 2 [consumers] => 2 [] => 2 [service] => 2 [through] => 2)

excepted output for my requirement is :
Array ( [product] => 2 [consumers] => 2 [] => 2 [service] => 2 [through] => 2)

bretticus

ah, the @ (at signs) were your delimiters. I'm more awake now. If this problem goes unsolved, I'll look at it again tomorrow. For now, it looks like you're in good hands with devphp12 .

kishore2k9

thanks for ur suggestions my problem is sloved .