[RESOLVED] Undefined constant error. Using variables in array key issue.

sois

I am getting this error:
Notice: Use of undefined constant USERID - assumed 'USERID' in /site/page.php on line 120

What is the proper way to code this line? I have an array and i want to use a variable in the array keys. Here is the offending line of code:

print "<td><input type='text' value='$b[TD]' name='stat[{$a[USERID]}][TD]' size=2></td>";

sois

I created a temporary work around. I assigned $a['USERID'] to $userID. That seems to work. I need some guidance on how to use the $a['VARIABLE']'s. This is what happens when you teach yourself 🙂

NogDog

Normally you should always use quotes around string literal array keys ($arr['key'] instead of $arr[key]), as you will get the undefined constant notice otherwise. There is an exception to that rule( :rolleyes: ) when using a array variable within a double-quoted string literal and not using the "complex notation" (i.e. the curly braces). I prefer to avoid using that no-quote option so as to keep consistent in my quoting of keys. Therefore any of the following should work (if I didn't make any typos):

print "<td><input type='text' value='".$b['TD']."' name='stat[".$a['USERID']."][TD]' size=2></td>";
print "<td><input type='text' value='{$b['TD']}' name='stat[{$a['USERID']}][TD]' size=2></td>";
sprintf(
   "<td><input type='text' value='%s' name='stat[%s][TD]' size=2></td>",
   $b['TD'],
   $a['USERID']
);

Scroll down the manual page on arrays for the section titled "Why is $foo[bar] wrong?" for more information.

sois

Thanks, I don't know why I can't get this through my thick skull 🙂