find and Exec statment in PHP not working

[ajd335]

Hi All,
I have a page in which user can enter first name,last name , date and according to that My script should search for the records which matches the above last n first names and print it.
I have the below code,
But seems not working..

<?php
$title = " Form";
echo "Hello";
 if(isset($_POST['fname'])) { $f1 =  $_POST['fname']; }

if (isset($_POST['lname'])) { $ll =  $_POST['lname']; }
if (isset($_POST['add'])) { $a1 =  $_POST['add']; }
if (isset($_POST['date'])) { $d1 =  $_POST['date']; }

$fullname = $l1.","f1;
echo "$fullname;
$dirname = "/home/gr/ereports/O1"  ;

$handle = opendir($dirname) or print "cant open";

$ans = shell_exec("find /home/gr/ereports/O1/$d1 -name \*.ps  -exec grep -i -e "$fullname" {} \;  -print; ");

?>

If i go on shell to home/gr/ereports/O1 and then write the code as below

find dirname -name "*.ps" -exec grep -i -e "CAK, SO" {} \; -print ;

Here in above "CAK , SO" in which CAK is the lastname n SO is the first name
its giving me the result perfectly.
I am thinking that the way I used the above statment in PHP is wrong..
Can anybody help me...
Thanks

[NogDog]

You need to escape the double quotes around the $fullname variable in your shell_exec string with back-slashes (or else use single quotes around it).

[ajd335]

NogDog;10886196 wrote:

You need to escape the double quotes around the $fullname variable in your shell_exec string with back-slashes (or else use single quotes around it).

Hi NogDog,
Still one thing missing is that

$ans = shell_exec("find /home/gr/ereports/O1/$d1 -name  "*.ps"  -exec grep -i -e $fullname {} \;  -print; ");

here "*.ps" is needed like that only..
I have tried

$ans = shell_exec("find /home/gr/ereports/O1/$d1 -name  /"/*.ps/"  -exec grep -i -e $fullname {} \;  -print; ");

I want to execute "*.ps" , M I using it correctly ?

[igorlopez]

Try using the escape character \ like this

$ans = shell_exec("find /home/gr/ereports/O1/$d1 -name  \"\\*.ps\"  -exec grep -i -e \"$fullname\" {} \\;  -print; ");

EDIT: forgot to add the missing "" around the $fullname variable. (I have probably missed something else as well since the test was just by echoing)

[ajd335]

igorlopez;10886561 wrote:

Try using the escape character \ like this

$ans = shell_exec("find /home/gr/ereports/O1/$d1 -name  \"\\*.ps\"  -exec grep -i -e \"$fullname\" {} \\;  -print; ");

EDIT: forgot to add the missing "" around the $fullname variable. (I have probably missed something else as well since the test was just by echoing)

Thanks a lot...
I was missing the one at end 🙂
thanks again.....