Convert 3 char month to integer

[asa_carter]

How do I convert a 3 char month (e.g. Mar) to it's integer equivalent?

[leatherback]

probably [man]strtotime[/man] has some options, or you could use an array:

$months = array(
'jan' => 1,
'feb' => 2,
'mar' => 3);

echo $months[2];

[asa_carter]

Thanks. I couldn't find an option in strtotime() for shortened months.

I just modified my function to allow for another array of vales instead of just text to display for each option. Can this be shortened though?

function populateSelects ($v, $va, $vva) {
  if (empty($vva))
    $vva = $va;
  for ($i=0; $i < count($va); $i++) {
    if ($v==$vva[$i])
      echo "<option selected value=\"$vva[$i]\">$va[$i]</option>\n";
    else
      echo "<option value=\"$vva[$i]\">$va[$i]</option>\n";
  }
}

$day_array = array ('Day:','1','2','3','4','5','6','7','8','9','10','11','12','13','14','15','16','17','18','19','20','21','22','23','24','25','26','27','28','29','30','31');
$month_array = array ('Month:','Jan','Feb','Mar','Apr','May','Jun','Jul','Aug','Sep','Oct','Nov','Dec');
$month_values_array = array ('0','1','2','3','4','5','6','7','8','9','10','11','12');

<select name="day"><? populateSelects ($day, $day_array, null); ?></select>
<select name="month"><? populateSelects ($month, $month_array, $month_values_array); ?></select>

[NogDog]

How about:

<?php
function populateSelects($array, $selected)
{
   foreach($array as $value => $text)
   {
      printf(
         "<option value='&#37;s'%s>%s</option>\n",
         $value,
         ($value == $selected) ? " selected='selected'" : '',
         $text
      );
   }
}

$months = array(1 => 'Jan', 'Feb', 'Mar', 'Apr', 'May', 'Jun', 'Jul', 'Aug',
   'Sep', 'Oct', 'Nov', 'Dec');
$days = range(0, 31);
array_shift($days); // get rid of the 0th element
?>
<label>Month:
<select name='month'>
<?php populateSelects($months, 9); ?>
</select>
</label>
<label>Day:
<select name='day'>
<?php populateSelects($days, 17); ?>
</select>
</label>

[asa_carter]

Thanks NogDog. I've learnt quite a lot from that. I was just wondering why not just set the days range from 1 to 31 though?

NogDog;10886972 wrote:

$days = range(0, 31);
array_shift($days); // get rid of the 0th element

[asa_carter]

Ah. I see. 1 becomes 0.

EDIT:

No. That's not right either. The 1st of the month still has an index of zero.

Off to bed now but I'll take another look in the morning.

If I use range to create an array of values, how can I insert a string at the first index?

[NogDog]

Crap, I forgot that array_shift() renumbers the keys if they are numerical. I guess instead of the array_shift() you could just do unset($days[0]), perhaps?

[asa_carter]

I found that I still needed to use the text as a value also.

How about this:

$dayArr = range(1, 31);
array_unshift($dayArr, 'Day:');
$monthArr = array('Month:', 'Jan', 'Feb', 'Mar', 'Apr', 'May', 'Jun', 'Jul', 'Aug', 'Sep', 'Oct', 'Nov', 'Dec');
$yearArr = range(2008,1908);
array_unshift($yearArr, 'Year:');

function populateSelects($array, $selected, $option) {
  foreach($array as $value => $text) {
    printf(
      "<option value=\"%s\"%s>%s</option>\n",
      ($option == true) ? $select = $value : $select = $text,
      ($select == $selected) ? " selected=\"selected\"" : "",
      $text
    );
  }
}

<select name="day"><? populateSelects ($dayArr, $day, false); ?></select>
<select name="month"><? populateSelects ($monthArr, $month, true); ?></select>
<select name="year"><? populateSelects ($yearArr, $year, false); ?></select>