php ajax dropdown

[crwtrue]

i added to my site a ajax dropdown which i founded from this site:

http://php-ajax-code.blogspot.com/2007/07/ajax-triple-dropdown-with-states-cities.html

i made some changes to the code. I added one hidden field to the car_dropdown.php file and one more if else to the car.php where it shows the info of the chosen car in a textarea it works but sould i do it some other way like making a javascript function which reads the option of the second dropdown?

Now it goes like car_dropdown->car(dropd1)->car_dropdown->car(dropd2)->
car_dropdown->car(hidden field)->result in textarea.

[djjjozsi]

:
If you wanted to do something other field,

replace
echo "Cities : <font id=cities><select>\n";
echo "<option value='0'>=== none ===</option> \n" ;
echo "</select></font>\n";
part, add another id name..

in the ajax php file, made an extension at this part:

from this:
else if ($data=='cities') { // second dropdown
echo "<select name='cities' >\n";

to this
echo "<select name='cities' onChange=\"dochange('new_field', this.value)\">\n";

and of course add another else in the ajax php file, to create the html source code for the 3th element you wanted.

I will create a generator for this you wanted to unlimited elementes 🙂

bye!

jjozsi

www.phpcode.hu

[djjjozsi]

As a matter a fact that php processing program has security problemes!

Let read about sql injection.