DateTime input.

ThatDaniel

So, I'm writing a script that automatically retrieves the user's timezone and then translates all of the dates, however, I seem to be having a problem with DateTime's input string.
It says that it should be able to take in any type of UNIX timestamp (according to the docs; I'm assuming this is what is returned from time() as well), this just isn't the case for me.


 public static function displayDate($date, $format = "Y-m-d H:i:s", $time_zone_name = null) { 

    if($time_zone_name == NULL) { 

        $time_zone_name = self::fetchTimezone();

    }

    $new_date = new DateTime($date, new DateTimeZone($time_zone_name));


    return $new_date->format($format);
 }



 public static function fetchTimezone() { 

    return $time_zone_name = timezone_name_from_abbr('', -$_COOKIE['time_zone_offset']*60, $_COOKIE['time_zone_dst']);

 }


Example/Usage: 

echo common::displayDate(time());

The problem is that all of the dates I store are saved as results from time() so all of the things are going in are UNIX integer timestamps.

Am I doing this wrong - I'm really lost. Any help would be much appreciated.
Dan

NogDog

It's probably going to be difficult to answer this without knowing anything about the DateTime class you are using.

Weedpacket

It would be PHP's own, is my guess. But that doesn't take a Unix timestamp in the constructor; the documentation says it expects a string in any of the formats that strtotime() accepts.

ThatDaniel

Yes, it is the DateTime that is supplied by PHP 5.1.5+

Since it does only accept values that strtotime() would accept, how exactly would I go about changing the variable?

NogDog

echo common::displayDate(date('Y-m-d H:i:s'));

ThatDaniel

Well, now thats a silly and somewhat unnecessary step, but also just as bad that I didn't notice that first.
Thanks for your help, I appreciate it.