[RESOLVED] Date to Julian Day Count?

[h4x0rmx]

This should be pretty easy, I just don't know how to do it.
I have a date string

$report_date_min = '2008-11-01';

I need to convert it to Julian Day Count using the function GregorianToJD();
This functions expects 3 parameters. I could use the substr to get what I need, but I'm wondering if there's a more professional way to do it.
Any suggestions?

[laserlight]

If the format is guaranteed to be 'yyyy-mm-dd' (or 'yyyy-dd-mm') then you could use [man]explode/man.

[h4x0rmx]

How did I not think of that?

Thanks!!!