could not get variables....

hanpedro

At test.php?abc=def,

test.php
<?
include_once(test2.php);

include_once(some($def));
echo $test = (some($def));
?>

from test2.php
<?
function some_f($def) {
....
case($def) {
return "/format.php"
break;
}
}

I expect

include_once(/format.php);

Where am I wrong?

djjjozsi

<?
switch ($_GET["abc"])
{
case "def":
$file="/format.php"
break;

case "ghi":
$file= "/ghi.php"
break;

default:
$file="default.php";
return;

}

include_once($file);

in your code, there is no data set into $def variable! if you put a variable into a link:

http://www.somewebsite.com/index.php?site=1

then in index.php you can check like this:

if($_GET["site"]==1)
include("mainpage.php");

or with a switch case:

switch($_GET["site"])
{
case "1":
include("mainpage.php");
break;

case "2":
include("site2.php");
break;

default:
include("404_error.php");
break;
}

hanpedro

Thank you for your kind and Quick reply.

djjjozsi;10893851 wrote:
<?
switch ($_GET["abc"])
{
case "def":
$file="/format.php"
break;

case "ghi":
$file= "/ghi.php"
break;

default:
$file="default.php";
return;

}

include_once($file);

?>

in your code, there is no data set into $def variable! if you put a variable into a link:

http://www.somewebsite.com/index.php?site=1

then in index.php you can check like this:

if($_GET["site"]==1)
include("mainpage.php");

or with a switch case:

switch($_GET["site"])
{
case "1":
include("mainpage.php");
break;

case "2":
include("site2.php");
break;

default:
include("404_error.php");
break;
}