How to display month and year in dropdownmenu dynamically?

Techissue2008

I need to show dropdownmenu for month and year and current month and year are checked.
I knew how to get the current system year and month with

<? $t=getdate();?><? echo $t["year"];?>-<? echo $t["mon"];?>

Q.1 I created a dropdownmenu, but how should I make the checked value to be <? echo $t["mon"];?> ?

Please choose month:
<select name="month" class="pulldownmenu">
<option value="01">January</option>
<option value="02">February</option>
<option value="03">March</option>
<option value="04">April</option>
<option value="05">May</option>
<option value="06">June</option>
<option value="07">July</option>
<option value="08">August</option>
<option value="09">September</option>
<option value="10">October</option>
<option value="11">November</option>
<option value="12">December</option>
</select>

Q.2 I need to display the checked value of current year too, and the dropdownmenu needs to show current year - 10 and +10, i.e. 1998 to 2018.
How can I do it with <? echo $t["year"];?>

Please choose year:
<select name="year" class="pulldownmenu">
<option value="2008">2008</option>
</select>

Thanks for help

Servyces

Techissue2008;10894553 wrote:
Q.1 I created a dropdownmenu, but how should I make the checked value to be <? echo $t["mon"];?> ?

You could achieve that like this:

<select name="month" class="pulldownmenu">
<option value="01"<?php if($t['mon']=='01') { echo ' selected'>; } ?>>January</option>
<option value="02"<?php if($t['mon']=='02') { echo ' selected'>; } ?>>February</option>
<option value="03"<?php if($t['mon']=='03') { echo ' selected'>; } ?>>March</option>
<option value="04"<?php if($t['mon']=='04') { echo ' selected'>; } ?>>April</option>
<option value="05"<?php if($t['mon']=='05') { echo ' selected'>; } ?>>May</option>
<option value="06"<?php if($t['mon']=='06') { echo ' selected'>; } ?>>June</option>
<option value="07"<?php if($t['mon']=='07') { echo ' selected'>; } ?>>July</option>
<option value="08"<?php if($t['mon']=='08') { echo ' selected'>; } ?>>August</option>
<option value="09"<?php if($t['mon']=='09') { echo ' selected'>; } ?>>September</option>
<option value="10"<?php if($t['mon']=='10') { echo ' selected'>; } ?>>October</option>
<option value="11"<?php if($t['mon']=='11') { echo ' selected'>; } ?>>November</option>
<option value="12"<?php if($t['mon']=='12') { echo ' selected'>; } ?>>December</option>
</select>

Techissue2008;10894553 wrote:
Q.2 I need to display the checked value of current year too, and the dropdownmenu needs to show current year - 10 and +10, i.e. 1998 to 2018.
How can I do it with <? echo $t["year"];?>

A for-loop should do this trick:

<select name="year" class="pulldownmenu">
for($year = ($t['year'] - 10);$year = ($t['year'] + 10);$year++;) {
    echo '<option value="' . $year . '"'; if($year==$t['year']) { echo 'selected'; } echo '>' . $year . '</option>';
}
</select>

Techissue2008

I changed a little of the year for loop code:

<? $t=getdate();?>
<select name="year" class="pulldownmenu">
<?php
for($yr = ($t["year"] - 10); $yr = ($t["year"] + 10); $yr++ )
{ ?>
<option value="<?php echo $yr ; if($yr==$t["year"]) { echo " selected"; } ?>"><?php echo $yr ?>
</option>
<?php } ?>
</select>

It just shows 2018 in all option values. What's wrong with it?

Techissue2008

I found the error <=