echo

[jwerre]

<?php
if (is_home()) {
$flashContent = '[kml_flashembed movie="http://www.myMovie.swf width="760"  height="380"' . '/' .']';
echo "<div id='flashContent'>" . $flashContent . "</div>";
}
?>

// this is what i get
<div id='flashContent'></div>

Anyone have any idea why $flashContent doesn't show up

thanks for the help

[php_dev]

Ensure that you are setting the variable, or that if you are declaring the variable, ensure it is not recieving a NULL value.

Somewhere in your script you need:
$flashContent='value';

Hope it helps,

php_dev

[YAOMK]

But he is setting $flashContent to a string. I believe the error is in the context of your code. Have a look at is_home() and see if that is preventing your code for running and thus printing something else to the screen. Also note that you are setting $flashContent to a literal string.

[jwerre]

It's posting fine if i put a space after the "[ " or if i put one before " ]" Any idea why that would be?

[php_dev]

Wow sorry I looked at that code differently (can definetly tell its a sunday)...maybe the space is working because without them PHP interprets the [] as an array index. Not quite sure what else it could be.

[laserlight]

jwerre wrote:

It's posting fine if i put a space after the "[ " or if i put one before " ]" Any idea why that would be?

That is strange since extra spaces should have no consequence. As a demonstration, I suggest that you try running this as a separate script:

<?php
function is_home() {
    return true;
}

if (is_home()) {
    $flashContent = '[kml_flashembed movie="http://www.myMovie.swf width="760"  height="380"' . '/' .']';
    echo "<div id='flashContent'>" . $flashContent . "</div>";
}
?>

Incidentally, note that you are probably missing a double quote after '"http://www.myMovie.swf', and that the concatenation of the '/' and ']' is unnecessary since it can be just one string literal (and in fact, as YAOMK implicitly observed, you do not need the $flashContent variable at all).

Actually, what are you trying to do? That the insertion of spaces after '[' or before ']' makes a difference suggests that something else is at work here that you did not mention.

php_dev wrote:

maybe the space is working because without them PHP interprets the [] as an array index

That is not possible since single quoted strings are used to initialise $flashContent. Even with double quoted strings it should not happen since no variable is embedded.