if sentence structure does not work.

[hanpedro]

if sentence structure is not easy.

I have two groups in db.
"b_teams" for boards
"m_group" for members

So, I want to check two groups at inde.php.
index.php
<?
include("go_to.php");
if ($b_teams) {
$b_teams = which_board($b_teams);
include($b_teams);
}
if ($m_group) {
$m_group = which_group($m_group);
include($m_group);
}
?>

go_to.php
<?
if ($b_teams) {
switch ($b_teams) {

case "t_masters":
$t_masters = "/team/t_maters/t_index.php";
return $t_masters;

case "s_masters":
$s_masters = "/team/t_maters/s_index.php";
return $s_masters;
}

}
if ($m_group) {
switch ($b_teams) {
case "m1_group":
$m_group = "/team/m_group/m1_index.php";
return $m_group;

case "m2_group":
$m_group = "/team/m_group/m2_index.php";
return $m_group;	
}

However, this doesn't work....

I need help for this problem.

Thanls in advance

[djjjozsi]

$variable=$_GET["variable"]; // if you get this variable from a link, use $_GET


switch ($variable)
{
case "1":
include("index2.php"); // include this file
/* you use return but you must use break... */
break; //i --> index2.php

case "2":
include("index3.php"); // include this file
break; //i --> index3.php

case "3":
header("Location: a.php"); // header command to change the location
break; //h --> a.php

case "4":
header("Location: b.php"); // header command to change the location
break; //h --> b.php

case "5":
print ("Not registered!"); // use print command
break; //p --> Not registered!

/*you can use default:  */
default:
print ("No site has selected!"); // use print command


}

[hanpedro]

djjjozsi,

Thank you for your valuable codes!!