[RESOLVED] Undefined variable

mosherben

Hi all,
I'm trying to display a variable as a hyperlink, after it has been edited by str_replace.

Here is my code:

foreach($article as $item)
{
?>
<AHREF="<?php $test=str_replace("articles","printerfriendlynews.php?newsid=",$article->link) ?> Title</a><br>
	<?PHP
}
?>

When I try and display this script, it says article is an undefined variable. How will I solve this problem?

Cheers,

bretticus

mosherben;10898956 wrote:

foreach($article as $item)
{
?>
<AHREF="<?php $test=str_replace("articles","printerfriendlynews.php?newsid=",$article->link) ?> Title</a><br>
	<?PHP
}
?>

So, according to your code, you want to replace the occurrence of the string "articles" with the string "printerfriendlynews.php?newsid=" in the link property of the object $article. However, you are using $article as an array because it is the array parameter of your foreach loop.

Which line does the undefined warning/error come from? The foreach line or the str_replace line? You $article variable is either an array or an object. It can't be both. (well, it can be in PHP5 but that iterates through the properties and methods of an object and that hardly seems useful in your application of this code.)

mosherben

Hi,
yes you are correct I want to replace "articles" with printerfriendlynews.php?newsid=". 🙂

Basicly, I am reading an RSS feed and the foreach loop is supposed to go through all the nodes in the feed. Link is the name of the node which contains a URL.

The error is on the str_replace line. 🙂

Cheers,

bretticus

Are you sure $article is an object?

What do you get with:

<?php
print_r($article); //place just before your loop.
?>

In other words, why iterate over $article and then use it directly inside the loop? Perhaps $item is the object with a link property? Anyhow, the print_r() above will give us more insight.