[RESOLVED] Oddity with defined() and constant()

[scrupul0us]

Well as I've learned today with constants, if you want to check if they are defined you use, well, defined() except it doesn't seem to work as expect

given:

define('foo','bar');

$var = 'foo';

if(defined(constant($var)))
{
echo constant($var);
}

now you'd think that since the constant is defined it would output... nope...

define('foo','bar');

$var = 'foo';

if(!defined(constant($var)))
{
echo constant($var);
}

negating the defined() is the only way I can get it to work and YES it does output the contents of the constant... tell me that's not weird

[NogDog]

The arg for defined() is a string, not the actual constant. Your code was actually checking to see if a constant named "bar" was defined.

define('foo', 'bar');
$var = 'foo';
if(defined($var))
{
   echo constant($var);
}

[scrupul0us]

well hooray for fixing my own issue:

define('foo','bar');

$var = 'foo';

if(defined($var))
{
echo constant($var);
} 

as defined() already implies its checking a constant there's no need to imply it with the constant() function

[scrupul0us]

ah nogger you beat me to it!

thanks for the quick follow up though