preg_match help

[bookbuyer2000]

How do I preg_match (or preg_match_all) to parse out all the digits in a string that start with the letter "v" ??

Here is my string:
$string = 'blah bla bla blahh blah v5.62 blah blah v88.20 blah v19.00';

The desired result:
5.62
88.20
19.00

Here is my code that does not work:
preg_match_all("/^{v/",$string,$matches);}
foreach($matches as $match){
print $match."\n";
}

Any ideas?😕

[nrg_alpha]

Perhaps something along the lines of:

$string = 'blah bla bla blahh blah v5.62 blah blah v88.20 blah v19.00';
preg_match_all('#v(\d+\.\d+)#', $string, $matches);
echo '<pre>'.print_r($matches[1], true);

[bookbuyer2000]

Thank you very much for your response, but for some reason it doesn't seem to print all of the numbers starting with the letter "v".

Also, instead of the "echo <pre>" style, is there a way to do a "foreach" like I have it?

I can't seem to code it to make the preg_match fill its array with all the digits, nor can I seem to be able to make it loop through that array and print everything in it, via a "foreach loop" ... :queasy:

[nrg_alpha]

It does capture all the numbers starting with v... I just displayed it as an array (a common method for debugging).. to do it the way you want, simply replace:

echo '<pre>'.print_r($matches[1], true);

with:

foreach($matches[1] as $val){
	echo $val . "<br />\n";
}

Ouput:

5.62
88.20
19.00

[bradgrafelman]

And if the pattern isn't matching something, we'd need an example. In the example string you gave us above, the general pattern seemed to be a 'v' followed by a floating point number. If you had integer numbers, for example, then we'd need to know that.

Otherwise, you can try modifying the regular expression syntax yourself; here's a good informational website: http://www.regular-expressions.info