Parse error

[jingahii]

I'm having a similar problem with another mock up

function a($a){ return gzinflate(base64_decode($a));}
while(!$b){
if(substr($a,0,4) == ‘eval’ || !$count){
$a = a(str_replace(Array(’eval(gzinflate(base64_decode(\”,’)));’),”,$a));
$count++;
}else
$b = true;
}
echo $a;

And this is the line 283:

$a = a(str_replace(Array(’eval(gzinflate(base64_decode(\”,’)));’),”,$a));

Please help.

[big_nerd]

Please be sure to enclose your code in [ php] [ /php] tags so that it comes out with proper char's.

try this:

function a($a){ return gzinflate(base64_decode($a));}
while(!$b){
if(substr($a,0,4) == 'eval' || !$count){
$a = a(str_replace(Array('eval(gzinflate(base64_decode( \'','\')));'),'',$a));
$count++;
}else
$b = true;
}
echo $a;

I have found in a VERY similar function here.

I hope this helps...

[bradgrafelman]

You have a bunch of fancy quotes in that code you posted. Did you copy and paste straight from the PHP source file? If so, that's your problem. Change all of the fancy/slanted quotes into regular single or double quotes (and get rid of your crappy editor while you're at it).

[jingahii]

Thanks guys, let me try it out....