images in rows not columns

[harkly]

I am pulling images from my database and am going to display all images from an artist on one page. What I want to be able to do is to display them in rows of 4 and however many columns that are needed. Can someone help me with the code to displaying them in the row?

Here is my code that displays them in 1 column.

            $result2 = mysql_query("SELECT * FROM image WHERE artid LIKE '$search' ORDER BY title") or die(mysql_error());
            $num_rows=mysql_num_rows($result2);

          if ($num_rows != "0")
            {
              $count = count(0);
              while ($r=mysql_fetch_array($result2))
                {	
                  $imgid=$r['imgid'];
                  $artid=$r['artid'];
                  $title=$r['title'];
                  $dtxt_1 =$r['dtxt_1'];
                  $dt=$r['dt'];
                  $medid=$r['medid'];
                  $size_inch=$r['size_inch'];
                  $size_cm=$r['size_cm'];
                  $musid=$r['musid'];
                  $movid=$r['movid'];
                  $genid=$r['genid'];
                  $perid=$r['perid'];
                  $bio=$r['bio'];
                  $keywords=$r['keywords'];
                  $notes=$r['notes'];
                  $verified=$r['verified'];

                //display the row

                  echo "<div id='artContent'>";
                    echo "<span class='image'>";
                      echo $count++ ;
                      echo ". <div class=img-shadow><a href='image/$artid/$imgid.jpg' class='thickbox' title='$title by $fullName'>
                              <img src='image/thumb/$artid/$imgid.jpg' border=0 width=75 height='100' title='$title by $fullName' align=left valign=top></a></div></span>";


                    echo "<span class='info'>";
                     echo "<a href='image.php?imgid=$r[imgid]' title='$title by $fullName'>".$title."</a> <br>".$dt."<br>".$medid."<br>".$bio." ";
                  echo "</span></div>";

                }
            }

[coldwerturkey]

somthing like

$i = 1;
while(...) {
  //...
  if ($i \% 4) {
    echo "<br />";
  }
  $i++;
}

[harkly]

Thanks. I tried that as well as a few others but I think my problem is where to place the code.

Here's how I used the above code - any help with working it in my code?

//pulls info for art work of the artist above 

        echo "<div id='title'>";
        echo "<h1>Works <br><img src='image/smLine.jpg'></h1></div>";

        $result2 = mysql_query("SELECT * FROM image WHERE artid LIKE '$search' ORDER BY title") or die(mysql_error());
        $num_rows=mysql_num_rows($result2);



$i = 1; 


          if ($num_rows != "0")
            {
              $count = count(0);
              while ($r=mysql_fetch_array($result2))

                {	
                  $imgid=$r['imgid'];
                  $artid=$r['artid'];
                  $title=$r['title'];
                  $dtxt_1 =$r['dtxt_1'];
                  $dt=$r['dt'];
                  $medid=$r['medid'];
                  $size_inch=$r['size_inch'];
                  $size_cm=$r['size_cm'];
                  $musid=$r['musid'];
                  $movid=$r['movid'];
                  $genid=$r['genid'];
                  $perid=$r['perid'];
                  $bio=$r['bio'];
                  $keywords=$r['keywords'];
                  $notes=$r['notes'];
                  $verified=$r['verified'];

                //display the row

 if ($i % 4) { 
    echo "<br />"; 


                      echo $count++ ;
                      echo "<a href='image/$artid/$imgid.jpg' class='thickbox' title='$title by $fullName'>
                              <img src='image/thumb/$artid/$imgid.jpg' border=0 width=75 height='100' title='$title by $fullName' align=left valign=top></a>";
                      echo "<a href='image.php?imgid=$r[imgid]' title='$title by $fullName'>".$title."</a> <br>".$dt."<br>".$medid."<br>".$bio." ";

}
                    }
  $i++; 


}

          else
            {
              echo " <div id='search2'>";
                echo "<h3>We currently do not have any art work for this artist.</h3>";
              echo " </div>";
            }
?>