php 4 redirect issue

crafterscafe

I have a simple form www.crafterscafe.com/contest.html when data is transmitted I would like to return the person to a new page like www.crafterscafe.com/thank_you.html

I know this must be simple but I am on PHP 4 and can't find resource information.

I called hosting company and they cant help. although in two weeks I will have php 5 I still can't figure it out.

help - please....

devinemke

look at [man]header[/man]. there are specific examples of redirection

crafterscafe

I actually want to send to a page after the submit occurs - here is the php file...

<HTML><HEAD><TITLE>form results</TITLE></HEAD><BODY>
<?php/ this page recieves and handles the date generated by contest.html.///trim the incoming data$Array["name"] = trim($Array["name"]);$Array["email"] = trim($Array["email"]);$Array["newsletter"] = trim($Array["newsletter"]);$Array["heard_about"] = trim($Array["heard_about"]);$Array["networking"] = trim($Array["networking"]);$Array["comments"] = trim($Array["comments"]);//set the variables for the database access:$Host = "mysql.ixwebhosting.com";$User = "smlwfar_pres";$Password = "myrealpassowrd here";$DBName = "smlwfar_contest";$TableName ="contesttwo";$Link = mysql_connect ($Host, $User, $Password);$Query="INSERT into $TableName values ('0', '$name', '$email', '$newsletter', '$heard_about', '$networking', '$comments')";

//this is where I would like to redirect to my thank you page.

if (mysql_db_query($DBName, $Query, $Link))
{ print ("Thank you for your entry!<br>\n");
} else {
print ("The query could not be executed!<br>\n");
}
mysql_close ($Link);?>

</BODY></HTML>

devinemke

did you bother following the [man]header[/man] link in my initial post? you might also want to have a look at Output Buffering Control and weedpacket's header primer.

crafterscafe

yes i did read all of it, however, I am not sure i am understanding how it would know to go there ONLY if the condition is true.

for instance, in the future i will want to make a condition that if x is true then go to page a if y is true go to page b

how do I do that?

devinemke

a simple example (with no real form validation)

<?php
<?php
function form()
{
	echo '
	<form action="" method="post">
	name: <input type="text" name="name" value="'; if (isset($_POST['name'])) {echo $_POST['name'];} echo '"><br>
	email: <input type="text" name="email" value="'; if (isset($_POST['email'])) {echo $_POST['email'];} echo '"><br>
	<input type="submit" name="submit" value="submit">
	</form>
	';
}

if (!isset($_POST['submit']))
{
	form();
}
else
{
	foreach ($_POST as $key => $value)
	{
		$value = trim($value);
		if ($value == '') {$errors[] = $key;}
		$_POST[$key] = $value;
	}

if (isset($errors))
{
	echo 'you forgot to fill in the following fields: ' . implode(', ', $errors) . '<br><br>';
	form();
}
else
{
	mysql_connect('host', 'user', 'password') or exit(mysql_error());
	mysql_select_db('dbname') or exit(mysql_error());

	extract($_POST);
	$result = mysql_query("INSERT INTO table SET name = '$name', email = '$email'") or exit(mysql_error());
	header('location: http://www.example.com/thank_you.html');
	exit();
}
}
?>

crafterscafe

i'm confused... I thought that you couldn't have more than one header reference? I am on php 4.4.7 , I tried adding the header at the top and getting rid of the entire if statement and then adding to if and not at the top. both times I get an error saying that I already referenced header.

thanks for you help with this -

here is my new code:

<HTML>
<BODY>
<?php
//header('Location: http://www.crafterscafe.com/');
/ this page recieves and handles the date generated by contest.html./
//trim the incoming data
$Array["name"] = trim
($Array["name"]);
$Array["email"] = trim
($Array["email"]);
$Array["newsletter"] = trim
($Array["newsletter"]);
$Array["heard_about"] = trim
($Array["heard_about"]);
$Array["networking"] = trim
($Array["networking"]);
$Array["comments"] = trim
($Array["comments"]);
//set the variables for the database access:
$Host = "mysql.ixwebhosting.com";
$User = "smlwfar_pres";
$Password = "Contest09";
$DBName = "smlwfar_contest";
$TableName ="contesttwo";
$Link = mysql_connect ($Host, $User, $Password);
$Query="INSERT into $TableName values ('0', '$name', '$email', '$newsletter', '$heard_about', '$networking', '$comments')";

if (mysql_db_query($DBName, $Query, $Link)) {
//print ("The query was successfully executed!<br>\n");
header ("location: http://crafterscafe.com/store/index.php?main_page=page&id=9");
exit;
} else {
print ("The query could not be executed!<br>\n");
}
mysql_close ($Link);?>
</BODY></HTML>

devinemke

again, i urge you to read this

crafterscafe

i read and re read - yes I can read I posted here because it is a newbie forum - trying to learn a new thing is hard enough but when the resource material is weak it makes it even harder.

I figured out the problem - the text that I do have has you start php files with html and body tags - when I removed them it works.

actually I got that tid bid from looking at another source - please be kind to us newbies - I am sure you were one once....

thank you anyway for your responses

devinemke

using the Output Buffering Control function you can have precise control over what and when data is pushed to the browser. another simple example (in pseudo-pseudo code ):

<?php
ob_start();
?>

<html>
<head>
<title>my output buffering test</title>
<body>

<?php
if (condition is TRUE)
{
	echo 'something to the browser';
}
else
{
	ob_end_clean();
	header('location: http://www.example.com/somepage.html');
	exit();	
}
?>

</body>
</html>

<?php
ob_end_flush();
?>

bradgrafelman

In the above case, however, it's my personal preference to move the processing code (that bit of PHP in the middle) to the front to eliminate the need for output buffering. To me, using output buffering to remedy the "Headers already sent" error is rubbish - instead of simply moving the code, you're instead making the server buffer some data in memory which you never intend to use anyway.