[RESOLVED] List files array help needed

[zzz]

I have a directory with files.

Files have the following name structure:

report_zone3_051709.doc
report_zone4_061208.doc

Currently I display the list of all reports in the directory by building an array first:

$dirHandle=opendir('/mydir/reports');

while ($file = readdir($dirHandle)) {
    if (($file != '.') && ($file != '..') ) {
		$month = substr($file, -10, 2);
		$day = substr($file, -8, 2);
        $year = substr($file, -6, 2); 
        $array[$file] = strtotime($year . $month . $day);
	    }
}

arsort($array);

I'd like to be able to show only reports by certain year. Say I have a var set:

$year = 09;

Not sure how to do that.

[bradgrafelman]

Is that date in the filename in the format of MMDDYY? If so, try using [man]glob/man with a pattern like "report*09.doc for the 2009 year.

[zzz]

I do not use db in this project. I just list all files in a particular directory. All files are MS Word .doc types and all have the same naming convention, ending with year, i.e.

report_zone3_051709.doc <- May 17 2009
report_zone4_061208.doc <- June 12 2008

[bradgrafelman]

Right... so did you try my suggestion above?

[zzz]

Oh, oops... Sorry about that...

Not really sure how I'd use it, although it looks promising. Currently I build the list via loop like this:

foreach ($array as $key => $value) {
....
}

And in my earlier post I build that $array. I had a feeling that's where I needed to use filter to include only certain files into that array. Am i following you or am I heading for the dark woods?..

[bradgrafelman]

Well that's why I suggested [man]glob/man - it would get rid of all of the code you posted above; it returns an array of file names that match the specified pattern.