Hello guys.
I see there is a few threads on this subject but i have this problem the code looks ok to me but i'm not really up to scratch with functions or classes. this is the error...
Parse error: syntax error, unexpected T_STRING, expecting T_OLD_FUNCTION or T_FUNCTION or T_VAR or '}' in /home/site/public_html/pfp/magazine/db.php on line 6
:queasy:
:queasy:
here is the code.
config.php
<?php
// ADMIN SETTINGS //
define ("ADMIN_PASSWORD", "PASS"); // Admin Password
define ("WEBSITE_NAME", "Flash Page Flip"); // Your Website Name
// MySQL SETTINGS //
define ("HOST","localhost"); // database host
define ("USR", "user"); // database username
define ("PSW", "pass"); // database password
define ("DB", "cms"); // database to use
// E-MAIL SETTINGS //
define ("MAIL_FROM_NAME","website admin"); // Sender Name
define ("MAIL_SENDER_EMAIL","sender@example.com"); // Sender E-mail
define ("MAIL_SENDER_USERNAME","sender@example.com"); // Sender E-mail Username
define ("MAIL_SENDER_PASSWORD","youremailpassword"); // Sender E-mail Password
define ("MAIL_SERVER","mail.example.com"); // Sender Mail Server
define ("CHAR_SET","8859-1"); // Mail Character Set Code
define ("STF_SUBJECT","Check This Out"); // Tell a Friend Mail Subject
define ("STF_LINK","www.example.com"); // Your Publication Link For Tell a Friend
define ("LOST_PASSWORD_SUBJECT","Your Login Information"); // Lost Password Mail Subject
?>
db.php
<?php
require_once("config.php");
class db_layer
{
private $conn;
function __construct()
{
}
public function getConnection()
{
if($this->conn == "")
{
$conn = mysql_connect(HOST,USR,PSW);
mysql_select_db(DB);
mysql_query("SET NAMES 'utf8' COLLATE 'utf8_unicode_ci';");
$this->conn = $conn;
}
return($conn);
}
public function execute_sql($arg_sql,&$arg_result,&$arg_error_msg)
{
$arg_sql = str_replace(';', ':', $arg_sql);
$this->getConnection();
if (!($arg_result = mysql_query($arg_sql)))
{
$arg_error_msg = "There was a problem With the Database".NL."Error : ".mysql_error().NL.NL;
$arg_error_msg .= "SQL = [".$arg_sql."]";
echo $arg_sql1= $arg_sql." ### ".mysql_error();
return FALSE;
}
else
{
return TRUE;
}
}
}
?>
if comment out the private $conn line it just moves on and gives me exactly the same error on line 11.
any insight would much appreciated!
thanks
