Using a PHP Function within a HTML FORM?

RayAdams23

I am trying to launch a PHP Function from a FORM;

Currently I am running the Action as a seperate PHP page - like below;

<form enctype="multipart/form-data" action="uploadCSV.php" method="POST">
Please choose a file: <input name="uploaded" type="file" /><br />
<input type="submit" value="Upload" />
</form>

But I am having difficulty returning a Success or Failure back to this PHP page - can you call a PHP function in the "action=" instead of calling a new PHP page?

Thanks for any help,
RA

dagon

RayAdams23;10917776 wrote:
can you call a PHP function in the "action=" instead of calling a new PHP page?

No.

why not submit to the same page the form is on, then you output 'success' or 'error' with the form for them to refill in

RayAdams23

Thanks for the response Dragon - sorry about cross post.

I get the you cannot call a fuction;

My goal was to just allow a users to browse out - select a file - upload it - and then get a confirmation that is DID / DIDNOT upload.

But since I had to call out to that seperate .php I couldn't achieve the status on the initial .php page. Attached is both files - kept very simple, and any suggestions would be appreciated. I have only been learning PHP for a couple of weeks so I don't realize what is even a 'stupid' question at this point.

PHP FILE <uploadForm.php>:
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8" />
<title>uploadForm</title>
</head>

<body>

<form enctype="multipart/form-data" action="uploadCSV.php" method="POST">
Please choose a file: <input name="uploaded" type="file" /><br />
<input type="submit" value="Upload" />
</form>

</body>
</html>

PHP FILE <uploadCSV.php>:
<?php

$target = "CSVupload.txt";
if(move_uploaded_file($_FILES['uploaded']['tmp_name'], $target)) {
echo "The file ". $target ." has been uploaded";
echo "<br/> $target";
}
else { echo "Sorry, there was a problem uploading your file.";
}

header("Location: uploadForm.php");

dagon

give this a go:

<?php 

if(!empty($_FILES['uploaded']['tmp_name'])){

$target= "CSVupload.txt";
if(move_uploaded_file($_FILES['uploaded']['tmp_name'],$target)){
	$result= "The file " . $target . " has been uploaded";
}else{
	$result= "Sorry, there was a problem uploading your file.";
}

}
?>

<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8" />
<title>uploadForm</title>
</head>

<body>

<?php 
if(!empty($result)){
	echo '<p>'.$result.'</p>';
}
?>

<form enctype="multipart/form-data" action="<?php echo $_SERVER['PHP_SELF']?>" method="POST">
Please choose a file: <input name="uploaded" type="file" /><br />
<input type="submit" value="Upload" /></form>

</body>
</html>

RayAdams23

That worked great - thanks..