[RESOLVED] help in counting

[rtipton]

i have the following code and i need help in trying to count what is in the value.
Here is the code:

 do { 
	$myhash6[$row_get_Requestedby_Jun['Originator_Submitter']][] = $row_get_Requestedby_Jun['Requested_By'];
	} while ($row_get_Requestedby_Jun = mysql_fetch_assoc($get_Requestedby_Jun));
	arsort ($myhash6);
	foreach ($myhash6 as $key6 => $value61){
	$count6 = count($value6);
	$count_region6=0;
	$count_noc6=0;
	$count_oss6=0;
	for ($i=0; $i<$count6; $i++){
	if ($value6[$i] != ('oss'|'OSS'|'noc'|'NOC')) 
	{
	$count_region6++;
	}
	if ($value6[$i] == ('OSS'|'oss'))
	{
	$count_oss6++;
	}
	if ($value6[$i] == ('noc'|'NOC'))
	{
	$count_noc6++;
	}
	}
	echo"
	<tr>
		<td><div align=\"center\">$key6</div></td>
		<td><div align=\"center\">$count_region6</div></td>
		<td><div align=\"center\">$count_oss6</div></td>
		<td><div align=\"center\">$count_noc6</div></td>
	</tr>";
	}

What I need to do is count all the records that do not have the oss OSS noc NOC.

[johanafm]

The problem is

('oss'|'OSS'|'noc'|'NOC')

which is a bitwise or on those 4 strings.

Strangely though, this operation seems to work differently on strings than numbers. Considering only the effect of ("oss"|"OSS"), I would have expected the result to be the string "OSS", or the equivalent of the code

$o = dechex(ord("o"));
$o .= dechex(ord("s"));
$o .= dechex(ord("s"));

$O = dechex(ord("O"));
$O .= dechex(ord("S"));
$O .= dechex(ord("S"));

$or = ($o | $O);

Where the result, $or, not surpisingly is 0x6f7373 which corresponds to the byte values for the string "OSS". It does after all correspond to the effect of (1|3), which is 3.

However, the effect of

$or = ("oss"|"OSS");

is "oss", which in my view corresponds to the result of (1|3) being 1. I'd be happy if someone could enlighten me on the why of this.

Anyway, what you want is

if ($value6[$i] != 'oss' && $value6[$i] != 'OSS' && $value6[$i] != 'noc' && $value6[$i] != 'NOC')

// ...
if ($value6[$i] == 'OSS' || $value6[$i] == 'oss'))

And do note the difference between the logical comparison OR operator '||', and the bitwise OR operator '|'.

[rtipton]

Thank you It works

[Weedpacket]

Bitwise operations on strings work byte-by-byte on the strings' character sequences.

[johanafm]

But why is ("oss" | "OSS") returning "oss" instead of "OSS"?

[Weedpacket]

OSS
79, 83 83
010011110101001101010011

oss
111, 115, 115 (that's 79+32, 83+32, 83+32 (there are reasons why ASCII is the way it is)
011011110111001101110011

010011110101001101010011 | 011011110111001101110011 = 011011110111001101110011

[johanafm]

Ah, it was my memory playing tricks on me. Been a long time since I had to care and now I thought 'A' started at 0x61 and 'a' at 0x41 instead of the other way around. Then it did actually work as I had expected it to.

Thanks

[rtipton]

thank you