[RESOLVED] Highlite part of a string and witin words

[Cobbe]

[reg-ex newbee]

I have this function from another thread here:

$keywords = "hel or ow r o oda";

$search_data = "hello world how are you today";

$searchWords = explode(' ', $keywords);
array_walk($searchWords, create_function('&$v, $k', '$v = "/\\b$v\\b/i";'));
$search_results = preg_replace($searchWords, '<strong>\\0</strong>', $search_data);

echo $search_results;

I want the result to look like this:

hello world how are you today

[johanafm]

If you ditch 'r' and 'o' as keywords, then get rid of the word boundaries from the regexp pattern, you will get the result you want (except for 'o' and 'r').

However, unless you do respect word boundaries, special care must be taken for any pattern matching parts of "strong"

[Cobbe]

johanafm;10922849 wrote:

...then get rid of the word boundaries from the regexp pattern, you will get the result you want (except for 'o' and 'r').

This is where i am the newbie 😕

Could you explain please ?

I figure we are talking about this part:

create_function('&$v, $k', '$v = "/\\b$v\\b/i";'))

Tried to remove the \b ...no luck 😕

Thanks

[scrupul0us]

\\b

is the word boundry, you have to remove both the leading and trailing from $v

[johanafm]

And the reason is that while the word boundary in regexp is the two characters \ and b, they're found inside a double quoted string which means you need to escape the backslash.

[Cobbe]

Hi all

Thanks for the inputs. I did what scrupul0us said and things works like a charm.

Thanks again!