Complex include with variable

[sciwaysoft]

I have a page index.php where I want to include a file thumb.php
In thumb.php there is an image variable.... i-e.

$img . ".jpg"

Can I include same thumb.php with different variables that each time thumb.php is called the file return image according to the variable.
For example;

include('includes/thumb.php?id=4');

this will include thumb.php and image will be 4.jpg

include('includes/thumb.php?id=5');

this will include thumb.php and image will be 5.jpg

[johanafm]

$iWantThisImage = 5;
require 'thumb.php';

where thumb.php

somehowUseASpecificImage($iWantThisImage)

or

require 'thumb.php';
putCodeInThumbPhpInsideAFunction(5);

where thumb.php

function putCodeInThumbPhpInsideAFunction($imageId) {};

or

// If it's on the same server it seems silly to retrieve it via the web server.
$image = file_get_contents('http://domain/thumb.php?id=5');

[kbc1]

I may have misunderstood your requirements here but why can't you just state the variable name bbefore you include the file as such:

$img = 5;
include("/includes/thumb.php");

$img = 9;
include("/includes/thumb.php");

$img = 10;
include("/includes/thumb.php");

$img = 22;
include("/includes/thumb.php");

??

[sciwaysoft]

Thanks kbc1, I have just realized that how easy PHP is and I should take it easy.....

[Weedpacket]

Ooh, if you're going to do that you might as well get the computer to do the boring repetitive part.

foreach(array(5, 9, 10, 22) as $img)
{
include("/includes/thumb.php");
}