[RESOLVED] PHP Array

prkarpi

Hello all.

I have this script:

#price array
$price = array("bol"=>"Highest First", "mal"=>"Lowest First");
$split = explode(', ',$price[$p]); 

#date array
$date = array("bol"=>"Newest First", "mal"=>"Oldest First");
$split = explode(', ',$date[$d]);

This code identifies $p(or $d) variables being sent from <a href="some code&p=bol(or mal).index.php. On the same page I have the following code written:

 foreach ($split as $list($date)) {
 echo $list;
}
foreach ($split as $list($price)) {
 echo $list;
}

This writes the $p variable or $d variable in the output "echo $list". My problem is that it gives an error saying that '") is missing on the line where "foreach" is written. I am sure that it is an easy fix... I just don't see it. Can someone see my mistake?

Thank you.

Weedpacket

None of "Highest First", "Lowest First", "Newest First" or "Oldest First" contain any commas, so what is the explode() for? That $split variable (and there is only one, despite what you try to do further down) isn't going to contain anything useful.

And you want to [font=monospace]echo $date[$d];[/font] instead of that pointless and broken foreach loop.

prkarpi

This works. Thank you. However, I need only one of the variables to be printed (either "bol", which equals to be "Highest First" or "mal", which is "Lowest First" - that will depend upon the variable chosen through the HTTP header. At this point it prints both... do you have that solution. Thank you again!

johanafm

Nothing else is needed (for $price. exact same structure for $date)

$price = array("bol"=>"Highest First", "mal"=>"Lowest First");

// assumes $p has been defined previously
echo $price[$p];

prkarpi

Thank you "Weedpacket & johanafm."