[RESOLVED] Get file (script) name

[mikawhat]

How can i get the working file name within an included file?
e.g. included_file.inc.php is included in index.php, from included_file.inc.php i'd like to get the main filename (index.php in this case), in order to use it for creating a link. I tried $_SERVER['PHP_SELF'] but this is taking include_file.inc.php as the file name.

[dagon]

print_r($_SERVER); i'm sure its one of them.

[djjjozsi]

i think your doing something wrong, becouse $_SERVER["PHP_SELF"] gives you back thefolder_yourin/index.php in your case.

<?php
print "<pre>";
print_r($_SERVER);
print "</pre>";
?>

[mikawhat]

Yes you are right. Indeed it displays index.php as $_SERVER['PHP_SELF']. But i still have a problem as i'm using index.php for an ajax script, and i actually need to get the name of the page calling the index.php.

So to use the real file names to avoid any further confusions, index.php is the main page. Somewhere in index.php i'm using ajax to call get_odds.php, which includes 1x2.inc.php. So, in 1x2.inc.php i'm using for links $_SERVER['PHP_SELF'] which will return the link as get_odds.php?something=xx.

Is it possible to get somehow the name of the page calling with ajax get_odds to php?

[mikawhat]

$_SERVER["HTTP_REFERER"] seems to be just perfect!

[dagon]

never trust $_SERVER["HTTP_REFERER"], it comes from the client and may not be populated or correct.

The address of the page (if any) which referred the user agent to the current page. This is set by the user agent. Not all user agents will set this, and some provide the ability to modify HTTP_REFERER as a feature. In short, it cannot really be trusted.