Please help me with this :(

[Leveecius]

Hey guys, let me start off by saying I'm kind of a n00b to PHP, but I'm learning fast. So I got a script for a registration page for my site (game I made), but everytime I go to register, it never brings up my registration page. So I manually typed in the page and got this error:

Parse error: syntax error, unexpected ';', expecting ')'

well here is line 54:

$msgnum					= -1;

Any ideas?

[NogDog]

The actual error is probably on the preceding line, exactly what it says: you have a mismatch in the number of "(" versus ")".

[scrupul0us]

we need to see a few lines before the line given

[Leveecius]

ok, I'll give a few lines for ya 🙂

<?php /* ------------------------- */

$newpass			= rand(100000,999999);

  $login					= $_POST['login'];

  $city						= $_POST['stad'];

  $email					= $_POST['email'];

  $recruiter					= $rec;

 $ctype						= $_POST['ctype'];

  ${"select$ctype"}				= "selected";





  if(isset($_POST['submit'])) {

$message					= Array(

"<b>Your login may only contain: A-Z, a-z, 0-9, _  - </b><BR><BR>",

"<b>Fill in a valid Email-Address</b><BR><BR>",

"<b>Select a Criminal Type</b><BR><BR>",

"<b>That login already exists in the database</b><BR><BR>",

"<b>That email already exists in the database</b><BR><BR>",

"<b>The Recruiter name can only contain A-Z, a-z, 0-9, _  - </b><BR><BR>", 



$msgnum					= -1;



if(preg_match('/^.+@.+\..+$/',$email) == 0)

  $msgnum					= 2;

else {

  $dbres					= mysql_query("SELECT `id` FROM `users` WHERE `login`='{$login}'");

  if(mysql_num_rows($dbres) > 0)

    $msgnum					= 4;

  $dbres					= mysql_query("SELECT `id` FROM `users` WHERE `email`='{$email}'");

  if(mysql_num_rows($dbres) > 0)

$msgnum					= 5;

if(preg_match('/^[a-zA-Z0-9_\-]+$/',$login) == 0)

    $msgnum					= 6;

 

[faifas]

perhaps you would like to close your Array(); ?