[RESOLVED] Variables Question

rulkster2

Is there a way to control a dynamic value within a variable.

For example, if I have a variable called:

$myvariable1answer1

And all I want to change is the number 1 in the variable, how do I go about doing that. I tried using a for loop but that did not work:

for ($i = 1; $i <= 100; $i++) {
$newvar[$i] = $myvariable[$i]answer[$i];
}

So if I echo say $newvar[22], the value I am looking for is $myvariable22answer22.

With the above code I got a parse error, If I put quotes around this line:

$newvar[$i] = "$myvariable[$i]answer[$i]";

And then do an echo of $newvar[$i] I get: answer22

Thanks for any help.

laserlight

The syntax that you are looking for is:

for ($i = 1; $i <= 100; $i++) {
    $newvar[$i] = ${'myvariable' . $i . 'answer' . $i};
}

However, if feasible I suggest that you use arrays instead of variable variables.

jaql

rulkster2;10931628 wrote:
Is there a way to control a dynamic value within a variable.

For example, if I have a variable called:

$myvariable1answer1

And all I want to change is the number 1 in the variable, how do I go about doing that. I tried using a for loop but that did not work:
for ($i = 1; $i <= 100; $i++) {
$newvar[$i] = $myvariable[$i]answer[$i];
}
So if I echo say $newvar[22], the value I am looking for is $myvariable22answer22.

With the above code I got a parse error, If I put quotes around this line:

$newvar[$i] = "$myvariable[$i]answer[$i]";

And then do an echo of $newvar[$i] I get: answer22

Thanks for any help.

You should probably take a look at this page 🙂

EDIT: Or listen to Laserlight 😛

rulkster2

Thanks, but that did not work. Just got a blank page when trying to echo the new variable.

for ($i = 1; $i <= 100; $i++) {
    $newvar[$i] = ${'myvariable' . $i . 'answer' . $i};
echo "$newvar[$i]<br>";
}

jaql

rulkster2;10931640 wrote:
Thanks, but that did not work. Just got a blank page when trying to echo the new variable.
for ($i = 1; $i <= 100; $i++) {
    $newvar[$i] = ${'myvariable' . $i . 'answer' . $i};
echo "$newvar[$i]<br>";
} 

Unless your $myvariableXanswerX variables previously contain something, You'll get a blank page because all you did was assign $myvariable0answer0 to $newvar[0], etc., which do not contain anything, hence a blank page.

If you view the source of your page, you probably have 100 <br>'s though 😛

Neville1985

rulkster2;10931640 wrote:
Thanks, but that did not work. Just got a blank page when trying to echo the new variable.

$newvar = array();
for ($i = 1; $i <= 100; $i++) {
    $newvar[$i] = ${'myvariable' . $i . 'answer' . $i};
} 
echo $newvar['<num>'];

replace <num> with desired array key.

I don't know exactly what you want, cause I don't see the point in making $newvar into an array during a for statement, unless you want to call the var later, if thats the case, wouldn't it be smarter to create the var before this time? Correct me if I'm wrong.