[RESOLVED] PHP Variable in Image Tag

artnow

Hi all

I'm trying to put a variable into an image tag like this:

<img src=http://www.somesite.com/add.asp?x=1234&y=ABC&z=<?php echo $user; ?> border=0 width=125 height=10>

It doesn't seem to be taking the z variable and it splits up the image code echoing all the stuff after the closing php tag onto the web page.

If I add a double quote around the z variable, the only thing it takes is the first double quote.

I've fiddled with it for quite a while and still can't seem to figure out how to do it properly.

Thanks,

Bob

sneakyimp

It's helpful that you've posted your PHP code. I'm confused about what kind of output you are getting. Does the echo statement output anything?

artnow

Not sure this answers your question adequately but here goes.

All three variables are posted to a database through the add.asp script. I don't have access to either the database or asp script so no changes can be made there.

The x and y variables are hardcoded and post correctly to the database. The z variable does not post anything (it's blank in the database) when coded as z=<?php echo $user; ?> and if I put quotes around the php part, then only the first double quote is posted to the database.

Now originally the $user variable comes via a javascript and I change it to a php variable and that seems to work correctly since I can echo $user and it displays correctly.

Change javascript variable to a php one:

<?php $email = "<script type='text/javascript'>formData.display('user')</script>"; ?>

Hope that explains enough since I don't think I know anything else.

Bob

sneakyimp

I'm still pretty confused about what you are trying to do and what the real problem is.

If you want to output the contents of a variable, echo is the way to do it (as long as it is just a number or string of text). You don't need to add quotes.

If your PHP script is trying to echo a var like $user and nothing comes out, chances are that's because there is no $user variable defined in your script. If you have a javascript variable in your page then that's an entirely different type of variable.

artnow

The more I try to explain, the more confused I get, so you're not alone in your confusion.

In essence, I am trying to get the user (z) from a javascript variable into a database through an asp script both of which I have no access to.

Problem is, the php variable $user in the form z=<?php echo $user; ?> is causing problems for some unkown reason. On top of that, the asp script which puts the $user into the databasse is initiated when and image is shown .... through an img src which I also can't change.

sneakyimp;10932421 wrote:
... If you want to output the contents of a variable, echo is the way to do it (as long as it is just a number or string of text). You don't need to add quotes...

Could the problem be that the $user is an email address as in, it contains an "@" and a period?

Bob

johanafm

Possibly. But if you look at the HTML code, what exactly does it contain in place of the php code?

Also, & is not ok to use as you have done in your src attribute, since & is not an ordinary character, it's a control character for HTML entities. What you want is &
Furthermore, if you have anything but ordinary characters, you need to

echo urlencode($user);

And possibly specify what character encoding to use as well.

artnow

I finally struck on something ... what I need is a unique variable, so originally, I automatically went for the user ... but nothing says I can't use another available variable ... such as $id where id is a unique number. This makes urlencode unnecessary. I tried it out and it seems to work ...

I reviewed the HTML and it seems that I mistyped here in the forum ... the javascript to php variable should have read $user and not $email ...

The scr attributes are out of my control ... I was given the img src code and can't change it other than to include a unique identifier for d, which is now $id with the appropriate changes to the script.

So here what seems to work:

Change javascript variable to a php one:

<?php $id= "<script type='text/javascript'>formData.display('id')</script>"; ?>

<img src=http://www.somesite.com/add.asp?x=1234&y=ABC&z=<?php echo $id; ?> border=0 width=125 height=10>

Thanks for all your help.

Bob