For each 2 images include a footer

[Z3RatuL]

Hey guys!

I'm trying to build yacht a presentation where at the end there will be a bunch of images.

The thing is that each page can have only two images and at the end and I must include a footer (with the company logo). I wonder how can I enter the footer after each second image. The code I use is a simple code that finds any file and displays it as an image.

$yachtname = ereg_replace(" ", "", $row['ad_headline']);
$directory = "images/entries/".$yachtname."/";
$images = scandir($directory); 
$ignore = Array(".", "..");
foreach($images as $curimg){
	if(!in_array($curimg, $ignore)) {
		echo "<center><img src=\"".$directory."/".$curimg."\" width=\"800\" /></center><br /><br />\n";
	}
}

and I can't figure out where to put the <div> code with the footer.

Thanks in advance guys!

[big_nerd]

There is a few questions I have for you,

If you can only display 2 images, and there are more than 2 imagers per folder/directory, how do you prevent it from displaying the first 2 images on every page?

Unless I am mistaken and this is not how it works, maybe you can clarify, or do you want that code to display 2 images THEN the footer DIV code?

[Z3RatuL]

It's what you said at the end...

At the first page I would like to display the first 2 images from a folder of say 16 images; then the footer and after that the following 2 images untill it loads all 16 images.

I hope you understood now 😃.

[scrupul0us]

$images = scandir($directory); 

creates an array holding all the files in directory... just call each image by its array position

position 0 and 1 should be "." and ".."... beyond that should be your images