If statement validating under false conditions

[capgrasdelusion]

The if statement within the for loop is validating when at least one condition is false. Any help would be greatly appreciated.

$Exp = 29; //set to 29 for test purposes.
if ($Exp <= 2)
{
$UserLevel = 1;
}
else
{
$LastLevelExp = 3;
$NextLevelExp = 7;
echo($Level);
for ($LevelCheck = 2; !isset($UserLevel); $LevelCheck++)
{
if($Exp << $NextLevelExp && $Exp >= $LastLevelExp)
{
$ExpCheckMult = $LastLevelExp * 1.05;
$ExpCheckAdd = $LevelCheck * 2;
$NextLevelExp = Round($ExpCheckMult + $ExpCheckAdd);
$UserLevel = $LevelCheck;
}
}
}

[johanafm]

This seems strange and means shift $Exp left by $NextLevel bits, which is the same as $Exp * $NextLevelBits ^2[code=php]
if($Exp << $NextLevelExp
[/code]
Shoudn't it be < instead of <<?

[capgrasdelusion]

Hey, thanks for the response, but I'm still having trouble. I read up on the shift operator, and I see why it would be just < (I was used to Java), but when I change it to a single < I get an error 500: Script Execution Failure, Premature end of script headers. Any further help qould be tremendous.

[paulnaj]

Seems to me that you will be stuck in an infinite loop anyway since with the example $Exp = 29, this condition ...

if($Exp < $NextLevelExp && $Exp >= $LastLevelExp){

... will NEVER be satisfied, and thus $UserLevel will never be set.

In fact, the only way this will not be an infinite loop is if 3 <= $Exp < 7, in which case the condition will be true in the very first loop and $UserLevel = 2.

Maybe you should explain what you're trying to achieve.

Paul 🙂