[RESOLVED] how to pass variable to page from menu

rtech

I have a website with a php page structured like this:

<html>
<head>
Appropriate stuff
</head>
<body>
<div ="header">
<?php include 'header.inc' ?>
</div>
<div ="menu">
<?php include 'menu.inc' ?>
</div>

I'll call this page "mypage.php" I would like to call this page from the menu and be able to pass the variable "$PageContent" to cause different include files to be loaded for the content section of the page. How do I do this?

Thanks for any help.

johanafm

<a href="mypage.php?PageContent=file1.php">file1</a>
<a href="mypage.php?PageContent=file2.php">file2</a>

mypage.php

// at the top of the page
$files = array('file1.php' => '', 'file2' => '');

$PageContent = $_GET['PageContent'];
// someone passed an unknown value. don't wanna let them include just any file
if (!isset($files[$PageContent])) {
	header('HTTP/1.1 404 Not Found');
}

// in the <div="content">
if (!isset($files[$PageContent]))
	echo '404 Not Found';
else
	require($PageContent);

rtech

johanafm,

Thank you