Random image on refresh

brunko

Hi, everybody.
Got a problem with a specific thing. I got lost when trying to make simple header image rotating with 2 other images after refresh.
Want to have different image in header after refreshing a browser and should be linkable as well.
here is the code I need to modify:

$style_td = ' style="background-image: url(\''.$setting['shop']['url'].'img/blue.jpg\')"';

Thanx for help.

johanafm

$imgs = array('red.jpg', 'blue.jpg', 'green.jpg');

$img = $imgs[array_rand($imgs)];

brunko

well....doesn,t work...gives me syntax error. It might have smthng with with this code at the beginning.

if($style!=''){

$style_td = ' style="background-image: url(\''.$setting['shop']['url'].'img/3.jpg\')"';

johanafm

Looks fine to me once it gets syntax highlighting

$style_td = ' style="background-image: url(\''.$setting['shop']['url'].'img/3.jpg\')"';

What's the error message? And the code from a few lines before the reported line?

brunko

This is a code from upper lines :

$page = whatPage();
if($page == 'department_pronej'){
  $addTdId = ' id="tr_pronej"';
  $style ='nej';
}

if($page == 'department_proni'){
  $addTdId = ' id="tr_proni"';
  $style ='ni';
}

if($page == 'department_prooba'){
  $addTdId = '';
  $style ='oba';
  }


if($style!=''){

$style_td = ' style="background-image: url(\''.$setting['shop']['url'].'img/2.jpg\')"';

//$style_repaired_to_table = '" style="background-image: url(\''.$setting['shop']['url'].'img/logo_pro'.$style.'.gif\')';
}

I,m not sure if I have to replace previous code with yours or just add it in the line.

and this is code frome style.php. It,s just a style but when I want to change pic manualy, I have to rewrite name of it in style.php as well.

.logotd{
 background: #fff url('img/2.jpg') no-repeat;
 width: 557px;
 height: 135px;
 vertical-align: top;
 }

Thanx for helping me out.

Neville1985

I store most of my img data in a db and then take it from there. For something like this, I would just hard code something like (just an example, with db object, untested):

function getRandAdvertIMG ($min, $max) {
 $img_num = rand($min, $max);
 $res = $db->doQuery("SELECT * FROM site_img_advert WHERE id = '".$rand_num."'");
 while ($img = $db->doArray($res, 1)) {
  echo "<img src=\"".$img['img_address']."\" alt=\"".$img['img_name']."\">";
 }
}

This is just a throw together, but it's pretty straight forward. The '$min, $max' vars are needed for the number gen, then changes the query string. Results in the image being output to screen. Obviously this is a very basic example, with no logging, page clicks all that jazz, but you get the idea. Can be expanded on very easily. I find this easier, but that's just me.