Hello mates.
I'm practicing my php knowledge in an XAMPP. I have this script :
<?php
$mysqli = new mysqli ("localhost", "testuser", "testpassword", "testdatabase");
$news = "
SELECT
DATE_FORMAT(date_membered, '%b %e %Y') AS FormatTime
FROM
users
";
$getNews = mysqli_query($mysqli, $news)
or die(mysqli_error($mysqli));
$result = mysql_query($getNews);
while ($newsInfo = mysqli_fetch_array($getNews))
{
$NDate = $newsInfo['FormatTime'];
}
echo $NDate;
mysqli_free_result($getNews);
mysqli_close($mysqli);
?>
Everytime I run this script, my expected output displays but with this warning:
Warning: mysql_query() expects parameter 1 to be string, object given in C:\xampp\htdocs\test\my_test.php on line 15.
How could I get rid of this? The line 15 it says is $result = mysql_query($getNews);.
Anyone? Thanks.