[RESOLVED] how can I do this

kingdm

Happy new year.

I am planning to create a form which will generate an output based on a given value.

This is my scenario. In the first page, user will be asked how many girlfriend does he have. Then when submitting it, an <input type="text"> fields will be shown (Name and Description).

My question is how will I create the loop for this? Say if I input 3 girlfriends, the generated field will be 3, 3 Name & Description.

laserlight

Well, are you able to use a loop to generate a form with $n number of sets of generated fields? If you are able to do that, it becomes just a matter of substituting $n with the initial input. You should validate that the input is a non-negative integer.

By the way, are you really asking guys to confess to having multiple girlfriends simultaneously? :o

kingdm

Hmm, well I'm trying to but I' having difficulties in understanding the loop here in php. Not like in C, here is that foreach something is used. I was asked to use php 🙂

Can you demonstrate me some simple usage of loop here in php?

By the way, are you really asking guys to confess to having multiple girlfriends simultaneously?

Yes. Part of requirements since I'm single now (slightly) 😉

laserlight

You should use a for loop, not a foreach loop.

kingdm

I didn't notice that for loop is also applicable here in php.

Can I ask once again, I use a <input type text> to get the value for the number of girlfriend, now when I $_POST it in a variable to be used in the for loop, is it already an integer?

kingdm

What seems to be wrong here in my script?

ask.php

<html>
<head>
<title>Ask GF</title>
</head>

<form method="post" action="ask2.php">

How many girlfriends you have now? (Honestly): <input type="text" name="answer" style="width: 30px;">
<br />
<input type="submit" name="submit" value="Submit">

</form>
</html>

ask2.php

<?php
$display = array();
$answer = $_POST['answer'];
for( $ctr = 0 ; $ctr <= $answer ; $ctr++)
{
	$display[] = "Name: <input type='text'> &nbsp; Description: <input type='text'>";
}
?>
<html>
<head>
<title>Show Display</title>
</head>
<body>
<?php echo $display; ?>
</body>
</html>

The array won't print. It prints only the word "Array". It's my first time to manipulate the for loop here in php, sorry for being quite dumb.

laserlight

kingdm wrote:
Can I ask once again, I use a <input type text> to get the value for the number of girlfriend, now when I $_POST it in a variable to be used in the for loop, is it already an integer?

It would be a string. Strings can be converted to integer type, but the user can enter garbage, so you should validate the input, unless you simply want to take the conversion to integer as-is.

kingdm wrote:
The array won't print. It prints only the word "Array". It's my first time to manipulate the for loop here in php, sorry for being quite dumb.

You should loop over the elements of the array and print them.

kingdm

Thanks for reminding me regarding the validation. I'll do it before finalizing 🙂

I did as you told me, thanks for that, here is my renew code:

<?php
$display = array();
$answer = $_POST['answer'];
for( $ctr = 1 ; $ctr <= $answer ; $ctr++)
{
	echo "Name: <input type='text'> &nbsp; Description: <input type='text'>";
	echo "<br />";

}
?>
<html>
<head>
<title>Show Display</title>
</head>
<body>

</body>
</html>

Now it does print, but what if I want it to be printed on the html part how can I do this? Its because I want to stick with my style in the html, if I print it on the for loop it wont follow the style of the html.

sudh

<?php
$display = array();
$answer = $_POST['answer'];

?>
<html>
<head>
<title>Show Display</title>
</head>
<body>
<?php for( $ctr = 0 ; $ctr <= $answer ; $ctr++)
{
echo = "Name: <input type='text'>   Description: <input type='text'>";
} ?>
</body>
</html>

laserlight

kingdm wrote:
Now it does print, but what if I want it to be printed on the html part how can I do this?

What do you mean?

kingdm

laserlight;10938087 wrote:
What do you mean?

The name and description printed by the for loop is on the top of the screen, its not on the proper area where it should be. I want it to be printed on a certain <div> in the html. How is that?

bradgrafelman

kingdm wrote:
I want it to be printed on a certain <div> in the html. How is that?

Move the PHP code to the correct location in the script.

kingdm

Huge thanks bradgrafelman. It works now.

bradgrafelman

Don't forget to mark this thread resolved (if it is) using the link under the Thread Tools menu above.

kingdm

I almost forgot, its done and running 😃