I get the message that ereg_replace() is deprecated.
So, I want to change the following line
to use [man]preg_replace[/man]

$text = "<p>".ereg_replace("(\n){2,}", "</p><p>", $text)."</p>";

Thanks!

    I found it out myself.
    Simply add / in begining and end.

    $text = "<p>".preg_replace("/(\n){2,}/", "</p><p>", $text)."</p>";

      Those slashes are called delimiters. Delimiters don't have to be slashes however.. they can be any non alpha-numeric, non whitespace non backslash character. You can read up about delimiters here:

      http://www.php.net/manual/en/regexp.reference.delimiters.php

      Also, from what I gather, you shouldn't need to use a capturing group for \n (as $1 isn't really being used). You could simply use /\n{2,}/

        Yes, right.
        No need to capture.
        I know we can use for example ## as delimiters.
        Actually I often prefer ## before //, because they have better visibility and differ more from other slashes, backslashes in the code.

        Thanks, nrg_alpha
        Good to have guys like you and Weedpacket, who can help us with more difficult regex.
        🙂

          halojoy;10940118 wrote:

          Yes, right.
          Good to have guys like you and Weedpacket, who can help us with more difficult regex.
          🙂

          Don't forget NogDog and Laserlight.. they're good with regex too! 😉

            3 months later

            hi nrg_alpha!
            can you read my new post??
            http://www.phpbuilder.com/board/showthread.php?p=10950755#post10950755

            [ i don't understand where am i wrong...
            (ereg_replace deprecated: ereg_replace(".<!-- [-listado_ini-] -->(.)<!-- [-listado_fin-] -->.","\1",$string);
            with: preg_replace("#.            (<!-- [-listado_ini-] -->)(.)(<!-- [-listado_fin-] -->).#e","$2",$string);
            this function doesn't work...) ]

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