[RESOLVED] Str_replace Headache

gotornot

Now i dont know if im asking to much but in a string replace i am looking to change {SHOWOFFERS} with a function is this possible?
All i get is just the function output not the function output inserted into the $details template im trying to use.

Help please its driving me mad.

Example:

$from = "{SHOWOFFERS}";
$to = showqblock();
$messagetext = str_replace($from, $to, $details);
echo $messagetext;

The Function is a form dynamicaaly created to ask for specific questions:
Example

function showqblock()
{
global $id;
global $affid;
global $programid;
// check to see if the program is live
$selpgq = "SELECT * FROM program WHERE id='$programid'";
$selpgr = mysql_query($selpgq);
$selpgrow = mysql_fetch_array($selpgr);
echo '<form name="form1" method="post" action="ms_dataprocess.php"><table width="350" border="0" cellspacing="1" cellpadding="1">';
if ($selpgrow["name"]=="1"){echo '<tr><td width="88"><div align="right"><font size="2">Name:</div></td><td width="255"><input type="text" name="name"></td></tr>';}
if ($selpgrow["surname"]=="1"){echo '<tr><td width="88"><div align="right"><font size="2">Surname:</div></td><td width="255"><input type="text" name="surname"></td></tr>';}
if ($selpgrow["email"]=="1"){echo '<tr><td width="88"><div align="right"><font size="2">Email:</div></td><td width="255"><input type="text" name="email"></td></tr>';}
$ipaddy = $_SERVER['REMOTE_ADDR'];
if ($selpgrow["ipaddress"]=="1")
{echo '<input type="hidden" name= "ip" value="'.$ipaddy.'">';}
// now go through and show any extra questions
$extq = "SELECT * FROM extraq WHERE programid='$programid'";
$extr = mysql_query($extq);
while ($extrow=mysql_fetch_array($extr))
{
echo '<tr><td width="88"><div align="right"><font size="2">'.$extrow["name"].':</div></td><td width="255"><input type="text" name="'.$extrow["id"].'"></td></tr>';
}
echo'<input name="affiliate" type="hidden" id="affiliate" value="' . $affid . '">
<input name="track" type="hidden" id="track" value="' . $track . '">
<input name="pid" type="hidden" id="pid" value="' . $programid . '">
<tr>
<td colspan="2"><div align="center">
<input type="submit" name="Submit" value="Submit">
</div></td>
</tr>
</table>
</form>';
}

Bjom

I'm not exactly sure what you want to do really. Could you explain again? And also please use [php ] [/php ] tags around your code along with proper indentation. ty

Bjom

halojoy

$to = showqblock();
this means $to will get the value returned from function.
But there is no data return at the end of function.
Just bunch of echo inside function.

I would try buffering all those echo in function
and then return the contents of output buffer.
This function might work, unless there is some other issue

<?php

function showqblock()
{
	global $id;
	global $affid;
	global $programid;
	// check to see if the program is live
	$selpgq = "SELECT * FROM program WHERE id='$programid'";
	$selpgr = mysql_query($selpgq);
	$selpgrow = mysql_fetch_array($selpgr);

ob_start(); //output buffer start

	echo '<form name="form1" method="post" action="ms_dataprocess.php"><table width="350" border="0" cellspacing="1" cellpadding="1">';
	if ($selpgrow["name"]=="1"){echo '<tr><td width="88"><div align="right"><font size="2">Name:</div></td><td width="255"><input type="text" name="name"></td></tr>';}
	if ($selpgrow["surname"]=="1"){echo '<tr><td width="88"><div align="right"><font size="2">Surname:</div></td><td width="255"><input type="text" name="surname"></td></tr>';}
	if ($selpgrow["email"]=="1"){echo '<tr><td width="88"><div align="right"><font size="2">Email:</div></td><td width="255"><input type="text" name="email"></td></tr>';}
	$ipaddy = $_SERVER['REMOTE_ADDR'];
	if ($selpgrow["ipaddress"]=="1")
	{echo '<input type="hidden" name= "ip" value="'.$ipaddy.'">';}
	// now go through and show any extra questions
	$extq = "SELECT * FROM extraq WHERE programid='$programid'";
	$extr = mysql_query($extq);
	while ($extrow=mysql_fetch_array($extr))
	{
	echo '<tr><td width="88"><div align="right"><font size="2">'.$extrow["name"].':</div></td><td width="255"><input type="text" name="'.$extrow["id"].'"></td></tr>';
	}
	echo'<input name="affiliate" type="hidden" id="affiliate" value="' . $affid . '">
	<input name="track" type="hidden" id="track" value="' . $track . '">
	<input name="pid" type="hidden" id="pid" value="' . $programid . '">
	<tr>
	<td colspan="2"><div align="center">
	<input type="submit" name="Submit" value="Submit">
	</div></td>
	</tr>
	</table>
	</form>';

$contents = ob_get_clean(); //get buffer contents and clean it

return $contents; // return it to outside world
}

gotornot

Ive tried that and still no joy.

Iside the details is a html page and somewhere in that html page is theis tag {SHOWOFFERS}
I wanted to replace the show offers tag with the dynamically created form acessed and processed by showqblock()

Hmm it just sems to over right the whole html instead of slotting in?

halojoy

Try this.
Put in some debug lines, temporary.
Just for to see what we have and what is happening.
This would solve it.

<?php

$from = "{SHOWOFFERS}";
$to = showqblock();
//$messagetext = str_replace($from, $to, $details);
//echo $messagetext;

echo $from.'<hr>'; //debugging
echo $to.'<hr>';
echo $details.'<hr>';
exit();

johanafm

I think you're missunderstanding the fundamental building blocks of a web application. A script runs on the server and its output is sent to the browser. Roughly at the same time the script ends, the browser receives the last data, and the page is fully loaded in the browser (disregarding possibly heavy side requests due to html markup, for example for images).
Now the script is no longer running. Nothing is kept alive on the server. It doesn't know about the form in the browser. It doesn't know about user input.

However, the form may be submitted, to the same script that created it, or to another script. It may be on the same server, but then again it may not be. This is indicated by the action attribute of the form.

Let's say it is handled by the same script that created it. Then you would start that script (or somewhere before echoing the form at least)

// Assuming the method attribute of the form is set to "post", otherwise you'd need to check $_GET
// Was the submit button clicked? Or more generally, was the a form input/select/textarea element whos name is "Submit"
if (isset($_POST['Submit'])) {
	# Here's your input. It could never be returned by showqblock. But the user may choose
	# to send a post request and here it is...
}
// If you only want to show the form before the user posts data. Otherwise, remove else {, as well as }
else {
	echo '<form....>';
}

gotornot

ive solved it the p[roblem was inside the function i was vcalling other functions yet hadnt included them in the page make up. Thankyou once again for your superb help!!!