image size

phpheadaches

Hi:

I have the following PHP right now to define my image:

Echo"<td><img src=$image_dir{$row['pix']}></td>";

How would I add an image width and height?

phpheadaches

Ok. So i did some research and tried the following:

Echo"<td><img src=$image_dir{$row['pix']['140']}></td>";

This resulted in my image disappearing and now I have a blank photo symbol. Not sure that I'm doing a good job discribing the results. Let's just say they weren't what I'm looking for. I need to reduce the image to a 140x100 size to display it.

TenaciousC

Do you mean you are trying to actually reduce the size on the server, or just the browser? If it's just the browser, why not just put width and height attributes into your img tag?

phpheadaches

Not trying to reduce the size on the server. Only trying to reduce the display size in the browser.

I tried the following:

Echo"<td><img src=$image_dir{$row['pix'] width="140" height="105"}></td>";

, but got the following error:

Parse error: syntax error, unexpected T_STRING, expecting '}' in /home/content/b/o/a/boatstuf/html/test/inventory.php on line 290

bradgrafelman

That's because you included the width and height tags inside of the curly braces. PHP evaluates anything inside those curly braces as a PHP variable.

The solution is to just add the HTML code outside of the braces, just like the rest of the HTML code that was already there.

halojoy

It is only this variable that needs {around}
{$row['pix']}

When you use any double quotes: "
..inside a double quoted string
echo "str"ing"; ... gives error
you must escape those inside, using: \"
echo "str\"ing"; .. correct

<?php

echo "<td><img src=\"$image_dir{$row['pix']}\" width=\"140\" height=\"105\" /></td>";

// equal to:
echo "<td>
<img
 src=\"$image_dir{$row['pix']}\"
 width=\"140\"
 height=\"105\"
 />
</td>";