[RESOLVED] hidden field

tommyrulez

The hidden field function always reports field as empty which is what I want, but it actually launches the form in a new window.


<?php


if (isset($_POST['submit'])) {


/************************ SERVER SIDE VALIDATION **************************************/
/********** This validation is useful if javascript is disabled in the browswer ***/

foreach($_POST as $key => $row)
{
$row = trim($row);
if($row == "")
{
$err .= urlencode("I\'m sorry, but ". $key. " is empty. \n");
header("Location: /Topten/bin/lib/Pollform.php?msg=$err");
exit();
}
}

if(!String.IsNullOrEmpty(Pollform.Form("thishiddenfield")))
{
form.reset();
$err = urlencode("ERROR: Unable to process!");
header("Location: /Topten/bin/lib/Pollform.php?msg=$err");
exit();
}

include 'db.php';
$sql_insert = "INSERT into `results`
  			(`fc`,`sec`,`tc`,`foc`,`fic`,`sic`,`sevc`,`ec`,'nc','tec'
			)
		    VALUES
		    ('$data[fc]','$data[sec]','$data[tc]','$data[foc]','$data[fic]','$data[sic]','$data[sevc]','$data[ec]','$data[nc]','$data[tec]',$data('count')
			)
			";

mysql_query($sql_insert,$con) or die("Insertion Failed:" . mysql_error());

$sql_insert = "INSERT into `users`
  			(`date`,`user'
			)
		    VALUES
		    (now(),'$pUser'
			)
			";

mysql_query($sql_insert,$con) or die("Insertion Failed:" . mysql_error());
form.reset();
}
echo "
<form action=\"/Topten/bin/lib/Pollform.php\" method=\"post\" name=\"pollForm\" id=\"currentsurvey\">
<table width=\"100%\" border=\"1\" cellspacing=\"5\" cellpadding=\"3\">
    <tr>
    <td width=\"30%\"><input type=\"text\" value=\""; if(isset($_POST["fc"])) echo "".$_POST["fc"].""; echo "\" name=\"fc\" ></td>
    <td width=\"70%\" rowspan=\"12\" align=\"left\" valign=\"top\">Welcome to this month's Survey. This month you get to decide: THE GREATEST MOVIE EVER!!!!
   	</td>
  </tr>
  <tr>
    <td><input type=\"text\" value=\""; if(isset($_POST["sec"])) echo "".$_POST["sec"].""; echo "\" name=\"sec\" ></td>
    </tr>
  <tr>
    <td><input type=\"text\" value=\""; if(isset($_POST["tc"])) echo "".$_POST["tc"].""; echo "\" name=\"tc\" ></td>
    </tr>
  <tr>
    <td><input type=\"text\" value=\""; if(isset($_POST["foc"])) echo "".$_POST["foc"].""; echo "\" name=\"foc\" ></td>
    </tr>
  <tr>
    <td><input type=\"text\" value=\""; if(isset($_POST["fic"])) echo "".$_POST["fic"].""; echo "\" name=\"fic\" ></td>
    </tr>
  <tr>
    <td><input type=\"text\" value=\""; if(isset($_POST["sic"])) echo "".$_POST["sic"].""; echo "\" name=\"sic\" ></td>
    </tr>
  <tr>
    <td><input type=\"text\" value=\""; if(isset($_POST["sevc"])) echo "".$_POST["sevc"].""; echo "\" name=\"sevc\" ></td>
    </tr>
  <tr>
    <td><input type=\"text\" value=\""; if(isset($_POST["ec"])) echo "".$_POST["ec"].""; echo "\" name=\"ec\" ></td>
    </tr>
  <tr>
    <td><input type=\"text\" value=\""; if(isset($_POST["nc"])) echo "".$_POST["nc"].""; echo "\" name=\"nc\" ></td>
    </tr>
    <td><input type=\"text\" value=\""; if(isset($_POST["tec"])) echo "".$_POST["tec"].""; echo "\" name=\"tec\" ></td>
    </tr>
      <td colspan=\"2\">
       <input type=\"hidden\" name=\"thishiddenField\" id=\"thishiddenField\" value=\"\" />
      <br/><input name=\"submit\" type=\"submit\" value=\"Submit\"> </td>
  </tr>
</table>
</form>";
?>

tommyrulez

Nevermind.

I had this line first.


foreach($_POST as $key => $row)
{
$row = trim($row);
if($row == "")
{
$err .= urlencode("I\'m sorry, but ". $key. " is empty. \n");
header("Location: /Topten/bin/lib/Pollform.php?msg=$err");
exit();
}
}

Which is always going to show the error

But now I am getting this error: Call to undefined function isnullorempty()
for:


if(!String.IsNullOrEmpty(Pollform.Form("thishiddenfield")))

should I use

if(!Empty(Pollform.Form("thishiddenfield")))

???

bradgrafelman

I'm not sure what language that's supposed to be, but it's definitely not PHP.

tommyrulez

bradgrafelman;10943990 wrote:
I'm not sure what language that's supposed to be, but it's definitely not PHP.

I took it off another page. Apparently it is C#, but what it was doing in a php form I have no idea. 😕

tommyrulez

I have another question about:

foreach($_POST as $key => $row)
{
$row = trim($row);
if($row == "")

for each $key or $row, do I have to assign it to the value I want it stored as or shouldn't:

<input type=\"text\" value=\""; if(isset($_POST["fc"]))

Store the value for me. I tried echo $row('tc'); and echo $key('tc'); and neither one works.
When I click submit all I get is a blank page

bradgrafelman

I don't know what you mean by "store the value for me." Do you mean you're trying to fill in the form fields with the user's previous submitted values? If so, then simply add an echo statemant after that if() statement to echo out the POST variable, e.g.:

if(isset($_POST(['fc'])) echo $_POST['fc'];

You could also use the ternary syntax to make it a bit more compact:

echo 'value="' . (isset($_POST['fc']) ? $_POST['fc'] : '') . '">';

I might also add that you should use something like [man]htmlentities/man rather than just outputting $_POST['fc'] so that whatever they submitted doesn't break your HTML syntax.

tommyrulez wrote:
I tried echo $row('tc'); and echo $key('tc'); and neither one works.
When I click submit all I get is a blank page

Neither works because both cause a parse error. You're getting a blank page because you haven't correctly configured display_errors and/or error_reporting (On and E_ALL, respectively, for example).

tommyrulez

Apparently, I am missing something from your example.


echo 'value="' . (isset($_POST['fc']) ? $_POST['fc'] : '') . '">';

I am getting an whitespace error:

<input type=\"text\"; echo 'value=\"' .(isset($_POST['fc']) ? $_POST['fc']: ''). '\">';

bradgrafelman

Hard to tell from that snippet of code, but it looks like you're missing some quotes in there.

Can you paste more of that code (a line or two above and below, for example)?

tommyrulez

I copied beginning of the form and right after. Yes, I had to have the action = like that because the form is called from another page 'include 'Pollform.php', it isn't until I hit submit that I have issues.

echo " 
<form action="Topten/bin/lib/Pollform.php\" method=\"post\" name=\"pollForm\" id=\"currentsurvey\">
  <table width=\"100%\" border=\"1\" cellspacing=\"5\" cellpadding=\"3\">
    <tr>
      <td width=\"30%\"><input type=\"text\"; echo 'value=\"'.(isset($_POST['fc']) ? $_POST['fc']:'').';\">'
      echo 'fc';
      </td>
      <td width=\"70%\" rowspan=\"12\" align=\"left\" valign=\"top\">Welcome to this month's Survey. This month you get to decide: THE GREATEST MOVIE EVER!!!!<br />
        There are fifteen fields to enter your top 15. Choose wisely, because you can enter your choices only once. </td>
    </tr>

bradgrafelman

Notice where the syntax highlighting goes funky? You didn't escape the double quotes around the form action.

Also, my example above used single quotes to delimit the string. Since you're using double quotes, you have to adjust that in my code snippet to match.

tommyrulez

:rolleyes: I actually fixed that after I had posted.

echo " 
<form action=\"/Topten/bin/lib/Pollform.php\" method=\"post\" name=\"pollForm\" id=\"currentsurvey\">
  <table width=\"100%\" border=\"1\" cellspacing=\"5\" cellpadding=\"3\">
    <tr>
      <td width=\"30%\"><input type=\"text\"; echo 'value=\"'.(isset($_POST['fc']) ? $_POST['fc']:'').';\">'
      echo 'fc';
      </td>

Sorry about that.

I also have.

if (isset($_POST['submit'])){
$fc=(filter($_POST['fc'])); and so on......

but I get undefined error 'fc', so it has something to do with the script.
I have also tried:

  <td><input type=\"text\" value=\""; if(isset($_post["sec"])) echo "".$_post["sec"].""; echo "\"  name=\"sec\">
      </td>

bradgrafelman

If you're getting undefined index 'fc' inside of the if() loop that checks for $_POST['submit'], then you might want to check the HTML of the form to make sure it looks right.

As for the code snippet you posted, $post should be $POST.

tommyrulez

Apparently, php doesn't like:

$fc=isset($_POST['fc']);

bradgrafelman

There's nothing wrong with that line - $fc will be a boolean TRUE or FALSE.