Determine if this folder is the last level within that folder?

Peuplarchie

Good day,
I'm working on a script and this script list folder in a html list.

Here is the code;


<html>

<head>

<style type="text/css">

ul {

  list-style-image: url(Icons/box_icon.png);



}



li li {

  list-style-image: url('Icons/open_book_icon.jpg');



}



li li li {

  list-style-image: url('Icons/gallery.gif');

}



</style>

</head>

<body>







<?PHP

function globDir($dir)

{

   $files = glob("$dir/*", GLOB_ONLYDIR);



 if(!empty($files))

   {

  echo "<ul>\n";



  foreach($files as $file)

  {

  echo "<li>";





  echo "<b>". basename($file)."</b>\n";



           globDir($file);

     echo "</li>\n";

  }

  echo "</ul>\n";

   }

}

globDir('Photos');

?>



</body>

</html>

example folder
|
- Folder 1
- Folder 2
|
- Folder2.1
|
- Folder3

The deal here is that I could go by CSS level of list but my problem is that sometime there is more subfolder yhat this example.

Is there a way that I can tell the last level folder to be written in bold ?

Thanks !

bpat1434

With CSS, no. You'll have to define a class, and use javascript to traverse the DOM and get the last child and apply that class to that last child.

Woops, sorry. Didn't see the PHP code after the HTML.

This does what you want; however, do note that ever level has a "last" element. But it can go for an arbitrary number of levels:

function globDir($dir)
{
    $folders = glob($dir.'/*', GLOB_ONLYDIR);
    if(empty($folders))
    {
        return '';
    }

// Set up a counter
$i = 1;
// Get the max amount of folders we have
$max = count($folders);

// Start a new list for these folders
$output = '';
foreach($folders as $folder)
{
    $output .= '<li';
    if($i++ == $max)
    {
        $output .= ' class="last"';
    }
    $output .= '>'.basename($folder);

    $path = str_replace($dir.'/', '', $folder);
    $subfolders = globDir($dir.'/'.$path);
    if(!empty($subfolders))
    {
        $output .= '<ul>'.$subfolders.'</ul>';
    }

    $output .= '</li>';
}

return $output;
}