[RESOLVED] Passing $POST values to SECOND php program

JerryStephen

OK, I've gotten myself into a design quandry and I'm not sure how to do this. I searched online manuals, sample code, even checked out a couple of library 'how to' books and I'm at a loss as to what I should do. Probably something simple, but ....you know.... "newbie" says it all, right?

I have an HTML page with a FORM -- different fields being enabled via "radio" buttons, etc. No problem here.

The 'Submit' buttons calls a php program with extensive edits based on the POSTed variables (ie: if($_POST['RdoType']== 'IA') { etc. where 'RdoType' is a radio button on the form for type of request). This page also works just fine...

At the bottom of this page are three buttons: "Back to Edit" which returns to the form's page to change entered values (works fine), "Cancel" which goes back to the page before the form page (also works fine), and a third button "Confirm" which I want to call another php generated page to do the actual writing to the mySQL database, generate an email to the user and another to our Case Administrator, and display a 'Confirmation Number' that the user can save.

The problem is, the $_POST variables don't exist in the second level php program...

What's the best way to get the 40 form fields into the second php program?

big_nerd

JerryStephen,

You have a few options, the most common is to use sessions.

Please read here for more information on sessions.

Effectively this is how you use them:

Set the session variable

session_start(); // required at the top of EVERY FILE you wish to use sessions, when you SET them or when you RETRIEVE them

$questionOne = $_POST['q1'];

// Validate $questionOne however you do...

$_SESSION['questionOne'] = $questionOne; // set the session

Then on the NEXT page (where you wish to pick up these values)

session_start(); // again, required

$questionOne = $_SESSION['questionOne'];

echo $questionOne;

Best of luck!

JerryStephen

Thank you big.nerd:

"You have a few options, the most common is to use sessions"

I was wondering about that -- guess I should have experimented with it a bit before posting this message, but to be honest I was burned out trying things that didn't seem to work!

I did discover that I only need ONE line per field:
$SESSION['RdoType'] = $POST['RdoType'] ;
seems to work just fine for me.

I tried to experiment with a single line, assigning $POST to $SESSION directly, but for now I'm going to put in all 40 some fields individually and worry about shortening the code after I get the rest of the code working!

Again, thank you for the help. It was greatly appreciated!!

Jerry