[RESOLVED] Active links in an included menu?

poker158149

Hi everyone.

I'm having a slight problem.

I'm using <?php include("menu.php") ?> to include my navigation menu so that I don't have to change every page whenever I want to change the menu.

However, I cannot give any of the links the "class='active'" tag so that the current page's link is different because it would have the same link active on every page since the same menu is included on every page. How can I make the link of the current page active when the menu is included?

bradgrafelman

Do some processing in menu.php to see which link is being requested and output the appropriate HTML.

TheoGB

Better yet, learn to use http://smarty.php.net and you'll be able to do your outputting with far more power.

poker158149

bradgrafelman, I am an amateur with PHP and do not know how to this processing.

Do you maybe have an example script I could look at?

bradgrafelman

It depends on how you define what "page" you're on. Are they in separate PHP scripts (e.g. "item1.php", "item2.php", etc. for each menu item)? Is there a variable in the query string? And so on.

Once you get the page name, you can do a simple if() statement for each link:

<a href="link1.php"<?php if($page == 'link1') echo ' class="active"' ?>>Link 1</a>
<!-- etc. for the rest of the links -->

fontener

you can also use CSS. By giving the body tag on the given page an id, and the link a class.

i.e.

<body id="homepage">

<a class="home" href="your page.html">link</a>

in your css

#homepage .home {your css attributes}

poker158149

Thank you both, I have it now figured out

bradgrafelman

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