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[evitapr]

I am having problems with my visual basic 2008 class I really need help!!
Can anybody help me please!!

[evitapr]

I need to do a program which I have to write a decimal number and the program will round the integer number and if the decimal part is less or the same as 0.25 u round the next integer and if the decimal part is more or the same as 0.75 it will remaine the same (3.79) if the decimal part is between 0.26 and 0.74 hope u understand thanks

[NogDog]

evitapr;10949782 wrote:

I am having problems with my visual basic 2008 class I really need help!!
Can anybody help me please!!

Well...this is a PHP forum, so while it's quite possible someone here could help, there would likely be a lot more people in a Visual Basic forum.

Should you want to solve your problem in PHP, you could do something like:

<?php
function myRound($value)
{
   $decimal = $value - floor($value);
   if($decimal <= .25)
   {
      $value = floor($value);
   }
   elseif($decimal >= .75)
   {
      $value = ceil($value);
   }
   return $value;
}

$values = array(5.24, 5.25, 5.26, 5.5, 5.74, 5.75, 5.76);
foreach($values as $val)
{
   echo "<p>$val: " . myRound($val) . "</p>\n";
}

[evitapr]

thanks I will try it

[evitapr]

ok for this program I made 2 textbox one name tbval and the other tbround and a button that is btresult I need to put in in the first textbox any decimal number and if I click the result buton in the tbround we will see the result. the result wil be the whole rounded as decimal number that means integer part for example if u write 3.79 and the decimal part is <= 0.25 then it will be 4.79 and if the decimal part is >= 0.75 will stays 3.79 if the decimal part is 0.26 and 0.74 hope u understand