[RESOLVED] Problem with function passing arguments

[lerro]

I have a function that i'm trying to use to pass arguments

This is the function which decides the option sql that is executed

function search_choice($choice, $fieldname)
   {  

       $choice  = $choice;
	   $fieldname  = $fieldname;


 	if ($this->record_status == "active")
	{
	   $query = $this->db->query("SELECT customer_type_id, customer_type, record_status FROM customer_type WHERE '$fieldname' = '$choice' AND record_status ='active' ");
	 }
	 else if ($this->record_status == "inactive")
	 {
	    $query = $this->db->query("SELECT customer_type_id, customer_type, record_status FROM customer_type WHERE '$fieldname' = '$choice' AND record_status ='inactive' ");
	 }
	 else 
	 {
	    $query = $this->db->query("SELECT customer_type_id, customer_type, record_status FROM customer_type");
	 }

	 return $query;

}

This is the function that sets the variable values and then calls the function at the top

function search_customertype()
    {
	 	$this->customer_type_id = $this->input->post('customer_type_id'); 
		$this->customer_type = $this->input->post('customer_type');
		$this->record_status = $this->input->post('record_status');

	$fieldname  = "customer_type";  
	$rec_status = $this->record_status;


	if ( !( $this->input->post('customer_type_id')))
	{
		$choice = $this->customer_type;
		$fieldname  = "customer_type";

		$query = $this->search_choice($choice, $fieldname);
	}
	else
	{		
		$choice = $this->customer_type_id;
		$fieldname  = "customer_type_id";

		$query = $this->search_choice($choice, $fieldname);
	}

     $query;

     return $query;

}

The problem is when i run the query in the form as shown below

<label>Customer Type ID
  <input type="text" name="customer_type_id">
  </label>
  <p>
    <label>Customer Type
    <input name="customer_type" type="text" size="27">
    </label>
  </p>

  <p>
      <label>Record Status:
     <select name="record_status" >
       <option value="">Any Status</option>
       <option value="active">Active</option>
       <option value="inactive">Inactive</option>
	   <option value="">Active and Inactive</option>
    </select>
  	</label>
  </p>

I don't get the expected output. When i enter Customer type id or Customertype, no value is returned. What's wrong in the above code?

[sneakyimp]

The function calls in search_customertype refer to variables which you have neglected to define inside those functions, namely $choice and $fieldname.

[lerro]

Thanks, i have resolved the problem