getimagesize doesn't work after server change ?

[MichaelHe]

Hi

I have a strange problem...
I have moved a site from one host to another and now one funktion is not working...

In an inmage upload script done with
<input name="upload" type="file">
and
move_uploaded_file($_FILES['upload']['tmp_name'], $uploadfile)
I upload an image...
But before I move the file I check the size and format this way

$image = getimagesize($_FILES['upload']['tmp_name']);
$type = $image['mime'];
$width = $image[0];
$height = $image[1];

IF($type == 'image/jpeg' AND $width == '200' AND $height == '150'){move_uploaded_file($_FILES['upload']['tmp_name'], $uploadfile);}

This has always worked, but now after I move the site to another host-server it doesn't work.
It won't upload the image and after a little research I can see that nomatter what I try to upload the parameters are just empty... $type, $width and $height is just nothing and therefore it won't upload offcause...

But why isn't this working... It has always worked fine, so it's only on the new server it doesn't work... Can anyone come with an explanation on this?

all the best
Michael

[NogDog]

For debugging, you might try something like:

ini_set('display_errors', 1); // set to 0 for production version
error_reporting(E_ALL);
$image = getimagesize($_FILES['upload']['tmp_name']); 
if($image === false) {
   user_error("getimagesize() returned false for file '". $_FILES['upload']['tmp_name'] ."'");
}
else {
   echo "<pre>DEBUG:\n";
   print_r($image);
   echo "</pre>\n";
}

One way or another, that ought to point us to where the problem is (assuming I don't have too many typos in there).

[MichaelHe]

Thank a lot for you fast answer :o)

Strangelly enough at writes

DEBUG:
Array
(
    [0] => 400
    [1] => 300
    [2] => 2
    [3] => width="400" height="300"
    [bits] => 8
    [channels] => 3
    [mime] => image/jpeg
)
Notice: Undefined variable: type in ******removed by me******.php on line 141 

So the size and type is clearly working but it is the $type that doesn't work or ?

[NogDog]

From what you've shown us, it seems like it should work. So I guess that begs the question: is there any code between where $image gets set and where you try to use it that you aren't showing us (maybe a simple typo or logic error is messing up something)?

[MichaelHe]

hmmm..

I researced a little more and I have actually written:

IF($upload>''){
$image = getimagesize($_FILES['upload']['tmp_name']);
$type = $image['mime'];
$width = $image[0];
$height = $image[1];
}

Because I have more than one image upload on the same page and I doesn't do this it types: Warning: getimagesize(): Filename cannot be empty on the uploades that has no image in them.. Therefore I have done it olike that so it only do the getimagesize on the imagefields changed by the consumer...

But for some reason $upload is empty... I do a simple <input name="upload" type="file"> in my form, and I actually don't see how this submit will automaticly put something in $upload when I do this if($POST){$id=$POST['ID'];} in the top of the page.. ID is the costumer ID btw ..

But I did it like this a long time ago and hasn't touched it since, and it has always worked ?

But is there another way to check if an image has been put in the input field ?