hey everyone

I was wondering if it'd be possible to generate a variable containing every word on a web page (given by url e.g. http://roblox.com/)
If so, how?

Thanks.

    Imperialoutpost;10958607 wrote:

    The easiest way I can think of is loading the page up with file_get_contents, and then use strip_tags to remove the code.

    You could then use a regex to remove punctuation, and explode the string in an array of individual words.

    file_get_contents doesn't work for me on other websites. fopen and fread do.

      cUrl gives you a lot more control...

      This is a basic version chopped down version of what I use for similar tasks:

      <?php

$ch = curl_init(); // Start the curl function

$userAgent =  'Googlebot/2.1 (http://www.googlebot.com/bot.html)'; // Set our UserAgent as Googlebot
curl_setopt($ch, CURLOPT_USERAGENT, $userAgent);

curl_setopt($ch, CURLOPT_URL, 'http://www.roblox.com/Default.aspx');
curl_setopt($ch, CURLOPT_FAILONERROR, true);
curl_setopt($ch, CURLOPT_FOLLOWLOCATION, true);
curl_setopt($ch, CURLOPT_AUTOREFERER, true);
curl_setopt($ch, CURLOPT_RETURNTRANSFER,true);
curl_setopt($ch, CURLOPT_TIMEOUT, 45);

$html = curl_exec($ch); // Pull the page HTML into the string $html

if (!$html) { // If it hasn't worked, print an error and fail

echo "cURL error number: " .curl_errno($ch) . '<br/>';
echo "cURL error:" . curl_error($ch) . '<br/>';
die();

}

echo strip_tags($html);

?>

      I notice if the useragent isn't set as Googlebot, then the site returns an error.

        I've found that it's helpful to forward the user agent of whoever is visiting your page.

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