Since the source of the string (html page) can have \n's in the string, this does not work:
preg_replace('/<p>(.*?)<\/p>/','\1', $A);
However, I am only guessing about the \n's since I am still trying to learn about Pattern creation. The string that was being replaced prints as follows when debugging:
<p>
August 4, 2010</p>
This pattern does work:
preg_replace('#</?p>#','', $A);
I greatly appreciate the help, yet I wish I could pop these patterns out with the ease that you appear to have.
Todd