Reversing preg_match_all

[baja]

The string array I am pulling dates/data out is ordered from newest to oldest and as such as I match it in the for loop it is put in the db in the reverse order from which i want it. I need to put the oldest in the db first and go newer at each insertion. There is an insertion of each match.

This is what I have. Some how it needs to match from end to beginning of the string, or reverse the array somehow.

// The $data could contain 20,000 matches to <entry>
preg_match_all ("/<entry>([^`]*?)<\/entry>/", $data, $matches);

foreach ($matches[0] as $match) {
   // pick out data, other_data
   insert date, other_data;
}

[bradgrafelman]

Well [man]array_reverse/man will reverse the order of the elements in an array, but I'm curious... why does it matter which order you insert them into the DB? Is there no "date" attribute in the data that would allow you to maintain the order in the DB?

[baja]

Yes, there is a date. This is the date that the data was added to the xml feed:

<published>2010-10-14T13:33:37.572209-08:00</published>

Short answer to your question. I need oldest in db first because of other progs accessing it. Newest must always be last, which is reverse order of xml feed given to me.

Having a hard time understand php arrays.

preg_match_all ("/<entry>([^`]*?)<\/entry>/", $data, $marray);

// Tried both ways, but still gives me the newest one first.

// $matches = array_reverse($marray);
// $matches = array_reverse($marray, true);

foreach ($matches[0] as $match) {

 preg_match ("/<published>([^`]*?)<\/published>/", $match, $temp);
 $published = $temp[1];

 // insert into db
}

[baja]

I am wondering if array_reverse does not work because of the type of array it is.

[baja]

Got it, thanks y'all.

$matches[0] = array_reverse($matches[0]);