All code on one page

ole_mariendal

Can some one help me, I want all php on one page.

I have make this, but that not working. I want it to go to page 100 and echo what there are.

<?php
header('Location: http://www.example.com/index.php?page=100');
if ($_GET['page'] === '100')
echo 'HTML code</a>';

if ($_GET['page'] === '101')
echo 'HTML code';
?>

dagon

your header call will immediately redirect the user to the page specified, so the code below wont get called.

ole_mariendal

How can I change that, I'm jst started with php, and I wont to learn it, can you give me an exempel?

dagon

what's the purpose for redirecting the user in the first place?

ole_mariendal

When a user going to the website, will the automaic go to index.php?page=100, so the user can see what there stand inside if ($_GET['page'] === '100')
echo 'HTML code</a>';

Thanks 🙂

dagon

but how will they ever see page 101 ?

ole_mariendal

The first page is 100, and then you have a links on this pages, maybe a menu. All I need are to take all me pages to you, and then switsh beetween them. But my scripts not working.

dagon

<?php
if (!isset[$_GET['page']]){
$_GET['page']='100';
}

if ($_GET['page'] == '100'){
echo 'HTML code page 100';
}elseif ($_GET['page'] == '101'){
echo 'HTML code page 101';
}

?>

ole_mariendal

I have this error Parse error: syntax error, unexpected '[', expecting '(' in

on this line

if (!isset[$_GET['logon']]){

ole_mariendal

if (!isset($_GET['logon'])){