static web form

PHPbeginner88

I have a text file called comment.txt, which says:

file text 300 a

file text 600 b

file text 700 c

file text 500 d

and what I want to do is display all comment details below a maximum price. The user will enter the price in a field on a static web form - the price is read in by the script and used to find the comment details as the script reads through the comment text file.

This is my code:

<HTML><BODY>

<?php
#reads a text file and outputs it to screen

 $prices = $_POST['price'];



$filename = "comment.txt";
$filepointer = fopen($filename, "r"); //open for read
$myarray = file ($filename);
for ($mycount = 0; $mycount < count($myarray); $mycount++)
    { //one line at a time
       $aline = $myarray[$mycount];
       $partdetails = getvalue($aline);
        print $partdetails[0]." <br>";
        print $partdetails[1]." <br>";
        print $partdetails[2]." <br>";
        print $partdetails[3]." <br>";
   }
$myprice = 0
if ($myprice == $prices)
 {
print = "the prices below $prices";
 }

 fclose ($filepointer);

 function getvalue ($text)
 {
     $intoarray = explode(",",$text);
     return $intoarray;
}

 // if (!($filepointer = fopen($filename,"r"))) { exit; }

 ?>

sneakyimp

You have not asked a question. Does your code work?

PHPbeginner88

No my code isn't working!

sneakyimp

What is "not working" about it.

PHPbeginner88

These sections:

$prices = $_POST['price'];

$myprice = 0
if ($myprice == $prices)
{
print = "the prices below $prices";
}

sneakyimp

this is a syntax error:

print = "the prices below $prices";

Are you trying to assign a value to a variable named "print"? If so, it should be $print, not print. Or are you trying to output some text to the browser? If that's the case, drop the equal sign.

PHPbeginner88

I don't want to assign print to a variable I just want to print out what's in the speech marks, what I'd like it to do is allow the user to enter a value into a static web form. And whatever the user types in it the shows everything below the value by using an if statement, from a file called comment.txt.

sneakyimp

so you have a lot of work to do to fix your script. let's start with the line i pointed out, shall we?

martyparty

Hi there 88, so i have worked out your PHP code and moreover worked out what you wanted to do

1/ let's assume form input value 45

2/ assume example comment.txt is

file text 50 a
file text 48 b
file text 47 c
file text 45 d
file text 44 e
file text 43 f
file text 42 g
file text 41 h

3/ note line values separated by space not comma

4/ here's the code

<?php
#reads a text file and outputs it to screen

//$prices = $_POST['price'];
$varprice = '44';
$prices = $varprice;

$filename = "comment.txt";
$filepointer = fopen($filename, "r"); //open for read
$myarray = file ($filename);
// get number of elements in array with count
for ($mycount = 0; $mycount < count($myarray); $mycount++)
{ //one line at a time
$aline = $myarray[$mycount];
//$partdetails = array();
$partdetails = getvalue($aline);

if ($partdetails[2] < $prices )
{
print $partdetails[0]." ";  
print $partdetails[1]." ";
print $partdetails[2]." ";
print $partdetails[3]." ";
print "<br><br>";
}

}

print "the prices below $prices";

fclose ($filepointer);

function getvalue($aline)
{
$intoarray = explode(" ",$aline);
return $intoarray;
}

// if (!($filepointer = fopen($filename,"r"))) { exit; }

?>

martyparty

So you need to compare the 3rd element in the array $partdetails[2] to get the match if it is less than

< $prices

Your function getValue had to be changed to split around a space not a comma.

PHP developer and web designer