how to find if the checkbox checked

PHPbeginner88

How do you find out if the checkbox has been checked?

this is my code:

<html><head> <title> checkbox </title> </head>
<body>

<FORM ACTION="comments.php" METHOD="POST">
Enter your comment <input type = "text" name = "username" value ="">

<p><input type ="submit" value="SUBMIT" name = "B1">
<input type = "reset" value="Reset" name = "SB2"
</form>
</html>

<?php
#reads a text file and outputs it to screen

if(!(isset($_POST['username']))) {exit;}

$uname = $_POST['username'];
print "The comments are: <br>";


$filename = "comments.txt";
$filepointer = fopen($filename, "r"); //open for read
$myarray = file ($filename);
for ($mycount = 0; $mycount < count($myarray); $mycount++)
    { //one line at a time
        $aline = $myarray[$mycount];
	$boxname = "box".$mycount;
        $partdetails = getvalue($aline);

if ($_POST['username'] > $partdetails[2])
{
print "$partdetails[0]<INPUT TYPE='checkbox' NAME='$boxname' ><br>";
print "$partdetails[1]<br>";
print "$partdetails[2]<br>";
print "$partdetails[3]<br><br>";

$myvalue = "$mycount";
print "<INPUT TYPE = 'hidden' NAME='mysecret' VALUE='$myvalue'>";
}


}




fclose ($filepointer);



function getvalue ($text)
{
    $intoarray = explode(",",$text);
    return $intoarray;
}

// if (!($filepointer = fopen($filename,"r"))) { exit; }


?>

Kudose

You need to give your checkbox a value and check if the value isset on POST

i.e.

<?php
  if(!empty($_POST)){
    if(!empty($_POST['something']))
      echo 'it was checked';
  }
?>
<input type="checkbox" name="something" value="1" />

PHPbeginner88

Thank you

how do I do: if it is checked "go to page 1"?

Kudose

Since you are outputting content to the browser before you make your check, you would need to use a meta refresh.

If you refactor the code to do your processing before outputting HTML to the browser, you can use a [man]header[/man] to do the redirect.

i.e.

if(!empty($_POST)){
    if(!empty($_POST['something'])){
      header('Location: http://www.phpbuilder.com/board/');
      exit;
    }
  }

PHPbeginner88

thank you

PHPbeginner88

It's not working. Do you know where in my code I should put it?

Kudose

Post up your code between [noparse]

[/noparse] tags

PHPbeginner88

It's not echoing. This is my code:

<html><head> <title> comment </title> </head>
<body>

<FORM ACTION="comment.php" METHOD="POST">
Enter a comment <input type = "text" name = "username" value ="">

<p><input type ="submit" value="SUBMIT" name = "B1">
<input type = "reset" value="Reset" name = "SB2"
</form>
</html>

<?php


#reads a text file and outputs it to screen

if(!(isset($_POST['username']))) {exit;}

$uname = $_POST['username'];
print "The prices below are: <br>";


$filename = "comment.txt";
$filepointer = fopen($filename, "r"); //open for read
$myarray = file ($filename);
for ($mycount = 0; $mycount < count($myarray); $mycount++)
    { //one line at a time
        $aline = $myarray[$mycount];
	$boxname = "box".$mycount;
        $partdetails = getvalue($aline);

if ($_POST['username'] > $partdetails[2])
{

if(!empty($_POST)){
    if(!empty($_POST['boxname']))
     echo 'it was checked';
  }

print "$partdetails[0]<input type='checkbox' name='boxname' value='1' /><br>";
print "$partdetails[1]<br>";
print "$partdetails[2]<br>";
print "$partdetails[3]<br><br>";

$myvalue = "$mycount";
print "<INPUT TYPE = 'hidden' NAME='mysecret' VALUE='$myvalue'>";




}


}




fclose ($filepointer);



function getvalue ($text)
{
    $intoarray = explode(",",$text);
    return $intoarray;
}

// if (!($filepointer = fopen($filename,"r"))) { exit; }


?>